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Dahasolnce [82]
4 years ago
11

You are part of a mission to Mars and have been assigned the task of designing balloons for the purpose of carrying scientific i

nstruments over the surface of the planet. You have been told that the density of the atmosphere at the surface is 0.0154 kg m3 . You have with you a tough plastic that has a mass of 5.0 grams per square meter. You plan to use the plastic to construct the balloons and inflate them with hydrogen gas. What would be the radius of a balloon that could hover over the surface
Physics
1 answer:
melomori [17]4 years ago
3 0

Answer:

<em>The radius of the balloon is R=  0.974 m</em>

Explanation:

Atmospheric density on the surface of mars ρ  = 0.0154 kg/m³

Mass  density of balloon σ  5 gm/m² = 0.005 kg/m²

Total mass of balloon M  = density of balloon* surface area

The balloon is considered as sphere

Surface area of sphere is given by  4π R²

Mass of balloon is M =σ *4πR²

                      M= (0.005 kg/m²)*(4π R²)

Volume of balloon is given by  \frac{4}{3} πR³

Density of atmosphere of mass is given by  

   ρ = Mass of balloon/volume of  balloon

       =(0.005 kg/m²)*(4π R²)/  \frac{4}{3} πR³

Re arranging R

R =  \frac{3*0.005 kg/m²}{ 0.0154 kg/m³}

   R = 0.974 m

<em>The radius of the balloon is R=  0.974 m</em>

<em></em>

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Answer:

The angular acceleration is 10.10 rad/s².

Explanation:

Given that,

Mass of sphere =220 g

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We need to calculate the angular acceleration

Using formula of torque

\tau=f\times r

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Here, I = moment of inertia of sphere

\dfrac{2}{5}mr^2\times\alpha=f\times r

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\alpha=\dfrac{5\times0.0200}{2\times220\times10^{-3}\times2.25\times10^{-2}}

\alpha=10.10\ rad/s^2

Hence, The angular acceleration is 10.10 rad/s².

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A ball that has a mass of 0.25 kg spins in a circle at the end of a 1.6 m rope. the ball moves at a tangential speed of 12.2 m/s
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The centripetal force acting on the ball will be 23.26 N.The direction of the centripetal force is always in the path of the center of the course.

<h3>What is centripetal force?</h3>

The force needed to move a body in a curved way is understood as centripetal force. This is a force that can be sensed from both the fixed frame and the spinning body's frame of concern.

The given data in the problem is;

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The centripetal force is found as;

\rm F_C = \frac{mv^2}{r}  \\\\ F_C = \frac{0.25 \times (12.2)^2}{1.6}  \\\\ F_C=23.26\ N

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To learn more about the centripetal force refer to the link;

brainly.com/question/10596517

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2 years ago
One of the harmonics on a string 1.30m long has a frequency of 15.60 Hz. The next higher harmonic has a frequency of 23.40 Hz. F
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Answer:

\large \boxed{\text{(a) 7.800 Hz; (b) 20.3 m/s; 40.6 m/s; 60.8 m/s}}

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\begin{array}{rcl}L & = & \dfrac{\lambda}{2}\\\\\text{1.30 m} & = & \dfrac{\lambda}{2}\\\\\lambda & = & \text{2.60 m}\\\end{array}

(b) Calculate the speed s

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\begin{array}{rcl}v_{2}& = & f_{2}\lambda\\& = & \text{15.60 s}^{-1} \times \text{2.60 m}\\& = & \textbf{40.6 m/s}\\\end{array}

\begin{array}{rcl}v_{3}& = & f_{3}\lambda\\& = & \text{23.40 s}^{-1} \times \text{2.60 m}\\& = & \textbf{60.8 m/s}\\\end{array}

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