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Harlamova29_29 [7]
4 years ago
5

To test the quality of a tennis ball, you drop it onto a floor from a height of 4.00m . It rebounds to a height of 2.00 m. If th

e ball is in contact with the floor for 12.0ms,
(a) What is the magnitude of its average acceleration during the contact?
(b) is the acceleration up or down?
Physics
1 answer:
mash [69]4 years ago
4 0
A. dont know
B. Up not down
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Answer:\frac{R}{3}

Explanation:

Given

Sphere of Radius R

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At any instant \theta Normal reaction(N) and weight(mg) is acting such that

mg\sin \theta -N=\frac{mv^2}{R}  , where v is velocity of block at any angle \theta

When block is just about to leave then N=0

therefore

mg\sin \theta =\frac{mv^2}{R}

v^2=gR\sin \theta-------------------1

Also by conserving Energy we get

Potential Energy=kinetic Energy of block

mgh=\frac{mv^2}{2}

here h=vertical distance traveled by block

From diagram

h=R-R\sin \theta

h=R(1-\sin \theta )

mgR(1-\sin \theta )=\frac{mv^2}{2}

2gR(1-\sin \theta )=v^2-----------------2

From 1 and  2

2(1-\sin \theta )=\sin \theta

3\sin \theta =2

\sin \theta =\frac{2}{3}

Thus from this value of h is

h=R(1-\sin \theta )

h=R(1-\frac{2}{3})

h=\frac{R}{3}

3 0
4 years ago
which of the following are vector quantities? check all that apply. a. acceleration b. mass c. displacement d. force
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What is the primary type of battery we use today to store energy?
Ahat [919]

Lithium-Ion batteries are commonly used in portable electronics and electric vehicles. These rechargeable batteries have two electrodes: one that's positively charged and contains lithium and another negative one that's typically made of graphite.

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likoan [24]

Answer:

v = 134.06 m/s

Explanation:

Given that,

Radius of a circular track is 1,835 m

Time required to complete one lap around a perfectly circular track is 86 seconds

We need to find the car's velocity. Velocity is equal to,

v=d/t

On circular path,

v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 1835}{86}\\\\v=134.06\ m/s

So, car's velocity is 134.06 m/s.

7 0
4 years ago
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