The formula for momentum is p = m*v
The conservation of momentum suggests:
m*vi = m*vf (initial mass times initial velocity = final mass times final velocity or initial momentum = final momentum)
(0.0010)(52.2) = (0.0010 + 3.3)vf
vf = (0.0010)(52.2)/(0.0010 + 3.3) = 0.0522/3.301 ≈ 0.01581 m/s
To the nearest thousandth ≈ .016 m/s
The attraction will decrease. Hope I helped :)
Cumulonimbus clouds are at a high level in the sky
D. 100 kilometers cuz the more kilometers the better the altitude!!!
The acceleration and distance is related to the following expression:
y=v0*t + a*t^2/2 ; v0=0
y=44.1*100/2 = 2205m
hence, the speed will be
v=0 + a*t = 441m/s
from that height it will just be subjected to the gravitational acceleration
0=v_acc^2 -2g*y_free
y_free = v_acc^2/2g = 9922.5m
<span>y_max = y_acc+y_free = 441+9922.5 =10363.5m</span>
