Answer:
0.13M and 0.16m.
Explanation:
Molarity is defined as the moles of solute present in 1L of solution.
Molality is the moles of solute per kg of solvent.
To solve this problem we need to convert the mass of sucrose to moles using its molar mass and finding the volume in L of the solution and the mass in kg of solvent:
<em>Moles sucrose: </em>
Molar mass:
12C = 12*12.01g/mol = 144.12g/mol
22H = 22*1.005g/mol = 22.11g/mol
11O = 11*16g/mol = 176g/mol
Molar mass of sucrose is 144.12g/mol + 22.11g/mol + 176g/mol = 342.23g/mol
Moles are:
19.0g * (1mol / 342.23g/mol) = 0.0555 moles of sucrose
<em>Liters solution:</em>
425mL * (1L / 1000mL) = 0.425L
<em>kg solvent:</em>
425mL * (0.82g/mol) = 348.5g * (1kg / 1000g) = 0.3485kg
<em>Molarity:</em>
0.0555 moles / 0.425L
<h3>0.13M</h3><h3 />
<em>Molality:</em>
0.0555 moles / 0.3485kg
<h3>0.16m</h3>
Answer:
write down each element and what you need to know about it repeatedly, and it will burn into your brain
Explanation:
Answer:
120.37 g
Explanation:
Mg = 24.31 g
S = 32.06 g
4 O = 16 X 4 = 64 g
Therefore, MgSO4 is (24.31 + 32.06 + 64) g = 120.37 g
Explanation:
Let us assume that the ratio for the given reaction is 1:1.
Therefore, we will calculate the moles of as follows.
Moles of solution = molarity × volume (L)
= 0.0440 M × 0.014 L
= 0.000616 moles
Moles of excess EDTA = 0.000616 moles
Also, the initial moles of EDTA will be calculated as follows.
Total initial moles of EDTA = 0.0600 M × 0.025 L
= 0.0015
Therefore, moles of EDTA reacted with will be as follows.
= 0.0015 - 0.000616
= 0.00088 moles
Since, we have supposed a 1 : 1 ratio between and EDTA
.
So, moles of = 0.00088 moles
Now, we will calculate the molarity of as follows.
Molarity of solution =
=
= 0.015 M
Thus, we can conclude that the original concentration of the solution is 0.015 M.
Answer: M= 128 g/mol (Te is quite close)
Explanation: number of Oxygen moles is n = 8 g / 32 g/mol = 0,25 mol.
Because formula of oxide is MO, thus amount of metal is also 0,25 mol.
Because n = m/M , Molar mass of the metal M = m/n = 32 g /0.25 mol = 128 g/ mol