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NeTakaya
3 years ago
12

A particular uranium alloy has a density of 18.75 g/cm3.

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
5 0

<em>I</em><em> </em><em>DONT</em><em> </em><em>KNOW</em><em> </em><em>THE</em><em> </em><em>ANSWER</em><em> </em><em>OF</em><em> </em><em>NO</em><em>.</em><em>B</em>

<em>SO</em><em> </em><em>SORRY</em><em> </em><em>FOR</em><em> </em><em>THAT</em><em>!</em><em>!</em><em>!</em>

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An unknown diprotic acid (H2A) requires 44.391 mL of 0.111 M NaOH to completely neutralize a 0.58 g sample. Calculate the approx
Anna [14]

Answer:

M=235.42g/mol

Explanation:

Hello!

In this case, given this is an acid-base neutralization and we are considering a diprotic acid, we can write the following mole-mole relationship:

2n_{acid}=n_{base}

It means that the moles of acid can be computed given the volume and concentration of NaOH:

n_{acid}=\frac{M_{base}V_{base}}{2} =\frac{0.044391L*0.111mol/L}{2} \\\\n_{acid}=2.46x10^{-4}mol

It means that the approximate molar mass of the acid is:

M=\frac{m_{acid}}{n_{acid}} \\\\M=\frac{m_{acid}}{n_{acid}} =\frac{0.58g}{2.46x10^{-3}mol}\\\\M=235.42g/mol

Best regards!

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saveliy_v [14]

Answer: Correct options are as follows.

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Explanation:

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As a result, both salt and water will retain their chemical properties.

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Answer: 6.61

Explanation:

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