Answer:
2Na=Ca(OH)000.1 AgBr=2KF 2KBr=LiNO
Answer:
C. Neither
Explanation:
According to the periodic table, Hydrogen is in group 1 and period 1. Beryllium is in group 2, period 2.
Answer: Option (3) is the correct answer.
Explanation:
When there is a negative charge on an atom then we add the charge with the number of electrons. Whereas when there is a positive charge on an atom then we subtract the charge from the number of electrons.
Atomic number of chlorine is 17. So, number of electrons present in
is 17 + 1 = 18 electrons.
Atomic number of cobalt is 27. So, number of electrons present in
is 27 - 4 = 23 electrons.
Atomic number of iron is 26. So, number of electrons present in
is 26 - 2 = 24 electrons.
Atomic number of vanadium is 23. So, number of electrons present in V is 23 electrons.
Atomic number of scandium is 21. So, number of electrons present in
is 21 + 2 = 23 electrons.
Thus, we can conclude that out of the given species,
has the greatest number of electrons.
Answer:
a. 27g/mol
b. 1.85 x 10^5 moles
Explanation:Please see attachment for explanation