The lower you go <span>in relation to the top of the atmosphere the larger the column of air is that is pressing down on you. </span>
<h2>
Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball</h2>
Explanation:
Kinetic energy = 0.5 x Mass x Velocity²
For ball of mass 2 kg
Mass, m = 2 kg
Velocity, v = 4 m/s
Kinetic energy = 0.5 x 2 x 4² = 16 J
For ball of mass 4 kg
Mass, m = 4 kg
Velocity, v = 2 m/s
Kinetic energy = 0.5 x 4 x 2² = 8 J
Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball
Answer:
A ) SOLID SPHERE
Explanation:
Moment of inertia of solid sphere = 2/5 M R²
= M K² , K is called radius of gyration
K = √2/5 R
Moment of inertia of solid cylinder = 1/2 M R²
= M K² , K is called radius of gyration
K = 1 /√2 R
Moment of inertia of solid sphere = M R²
= M K² , K is called radius of gyration
K = R
For rolling on inclined plane , acceleration
a = 
Putting the value of K for solid sphere
a for solid sphere
a = g sinθ / ( 1 +2/5)
a = .714 g sinθ
Putting the value of K for solid cylinder
a for solid cylinder
a = g sinθ / ( 1 +1/2)
a = .666 g sinθ
Putting the value of K for hollow pipe
a for hollow pipe
a = g sinθ / ( 1 +1 )
a = . 5 g sinθ
So we see that acceleration a for solid sphere is greatest and a for hollow pipe is the least. Hence solid sphere will reach the bottom earliest and hollow pipe will reach the bottom the latest.
Answer:
d = 1.24 kg/m³
v = 0.81 m³/kg
Explanation:
To do this, we need to analyze the given data and know the expressions we need to use here to do calculations.
We have a pressure of 1.05 atm and 300 K of temperature. To determine the density, we need to use a similar expression of an ideal gas. In this case, instead of using moles, we will use density:
P = dRT
d = P/RT (1)
Where:
R: universal constant of gases
d: density.
From here we can determine the specific volume by using the following expression:
v = 1/d (2)
Now, as we are looking for density, we need to convert the units of pressure in atm to Pascal (or N/m) and the conversion is the following:
P = 1.05 atm * 1.013x10⁵ N/m atm = 106,365 N/m
Now, using R as 287 the density would be:
d = 106,365 / (287 * 300)
<h2>
d = 1.24 kg/m³</h2>
Finally the specific volume:
v = 1 / 1.41
<h2>
v = 0.81 m³/kg</h2>
Hope this helps
