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Olin [163]
3 years ago
15

Which explains the information needed to calculate speed and velocity?

Physics
2 answers:
goblinko [34]3 years ago
8 0

The second statement is the correct choice.  Don't make me type it out.

Klio2033 [76]3 years ago
8 0

Answer:

B is the answer.

Explanation:

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A 20 cm-long wire carrying a current of 6 A is immersed in a uniform magnetic field of 3 T. If the magnetic field is oriented at
SOVA2 [1]

Answer:

the  magnitude of the force that the wire will experience = 1.8 N

Explanation:

The force on a current carrying wire placed in a magnetic field is :

F = Idl × B

where:

I = current flowing through the wire

dl = length of the wire

B = magnetic field

We can equally say that :

|F| = IdlBsin \theta

where : sin θ is the angle at which the orientation from the magnetic field  to the wire occurs = 30°

Then;

|F| = B\ I \ L \ sin \theta

Given that:

L = 20 cm = 0.2 m

I = 6 A

B = 3 T

θ = 30°

Then:

F = 3 × 6 × 0.2 sin 30°

F = 1.8 N

Therefore, the  magnitude of the force that the wire will experience = 1.8 N

6 0
3 years ago
I DO NOT WANT LINKES OR …………..
il63 [147K]

1st B is correct option

2nd D is correct option

4 0
2 years ago
Read 2 more answers
Help please it's a test
UNO [17]
Unbalanced. _______ and not equal.  in not sure about the 2nd choice from the info im looking at. the balanced version is 2NaOH<span> + </span><span>H2SO4</span><span> = </span><span>Na2SO4</span><span> + </span>2<span>H2O
(i hope this helps a little)</span>
7 0
3 years ago
Read 2 more answers
Which is not an example of a force?
NNADVOKAT [17]

Answer:

possibly A?

Explanation:

just feels right man

7 0
2 years ago
A catapult used by medieval armies hurls a stone of mass 32.0 kg with a velocity of 50.0 m/s at a 30.0 degree angle above the ho
NISA [10]

Answer:

The horizontal distance traveled when the stone returns to its original height = 220.81 m

Explanation:

Considering vertical motion of catapult:-

At maximum height,

Initial velocity, u =  50 sin30 = 25 m/s

Acceleration , a = -9.81 m/s²

Final velocity, v = 0 m/s

We have equation of motion v = u + at

Substituting

    v = u + at

    0 = 25  - 9.81 x t

    t = 2.55 s

Time of flight = 2 x Time to reach maximum height = 2 x 2.55 = 3.1 s

Considering horizontal motion of catapult:-

Initial velocity, u =  50 cos30 = 43.30 m/s

Acceleration , a = 0 m/s²

Time, t = 5.10 s

We have equation of motion s= ut + 0.5 at²

Substituting

   s= ut + 0.5 at²

   s = 43.30 x 5.10 + 0.5 x 0 x 5.10²

  s = 220.81 m

The horizontal distance traveled when the stone returns to its original height = 220.81 m

5 0
3 years ago
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