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Simora [160]
2 years ago
11

ONLY NEED PART B HELP

Mathematics
1 answer:
bezimeni [28]2 years ago
4 0

Answer: 48 model cars

Step-by-step explanation: 1. You know that the ratio of the number of model cars that Jim owns to the number of model cars Terrence owns is 4:3.

2. Let's call the number of model cars that Jim owns is , therefore, you can solve the exercise as following:

3. Therefore, Jims owns 48 model cars.

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The time it takes you to go a certain distance varies inversely with the speed of travel. Suppose it takes you 4 hours to get to
fgiga [73]
\bf \qquad \qquad \textit{inverse proportional variation}
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\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad  y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------

\bf \textit{time it takes varies inversely with the speed rate}\qquad \stackrel{time}{t}=\cfrac{k}{\stackrel{rate}{r}}
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\textit{we also know that }
\begin{cases}
t=\stackrel{hrs}{4}\\
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\end{cases}\implies 4=\cfrac{k}{50}\implies 200=k
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\textit{if your rate r = 40, what is your distance \underline{t}?}\qquad t=\cfrac{200}{40}
3 0
3 years ago
The length of one side of a square is 3n+2. The perimeter of the square is 4(3n+2). Which expression is equivalent to the perime
deff fn [24]

Answer:

4(3n + 2)

Step-by-step explanation:

as we know perimeter of a square is 4 x side

one side is 3n + 2

4 sides = 4(3n +2)

8 0
3 years ago
Write the interval (5,100] as an inequality and using set notation
drek231 [11]

Answer: { x | 5 < x ≤ 100 }  OR  { x ∈ ℝ | 5 < x ≤ 100 }

Step-by-step explanation:

{ x | 5 < x ≤ 100 }

This means:

"The set of all x's, such that x is greater than 5 and less than or equal to 100"

Another acceptable way to write this is

{ x ∈ ℝ | 5 < x ≤ 100 }

"x ∈ ℝ" simply means x is an element of all real numbers

7 0
3 years ago
The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili
Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean of a population is 74 and the standard deviation is 15.

This means that \mu = 74, \sigma = 15

Question a:

Sample of 36 means that n = 36, s = \frac{15}{\sqrt{36}} = 2.5

This probability is 1 subtracted by the pvalue of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{78 - 74}{2.5}

Z = 1.6

Z = 1.6 has a pvalue of 0.9452

1 - 0.9452 = 0.0548

0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

Question b:

Sample of 150 means that n = 150, s = \frac{15}{\sqrt{150}} = 1.2247

This probability is the pvalue of Z when X = 77 subtracted by the pvalue of Z when X = 71. So

X = 77

Z = \frac{X - \mu}{s}

Z = \frac{77 - 74}{1.2274}

Z = 2.45

Z = 2.45 has a pvalue of 0.9929

X = 71

Z = \frac{X - \mu}{s}

Z = \frac{71 - 74}{1.2274}

Z = -2.45

Z = -2.45 has a pvalue of 0.0071

0.9929 - 0.0071 = 0.9858

0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c. A random sample of size 219 yielding a sample mean of less than 74.2

Sample size of 219 means that n = 219, s = \frac{15}{\sqrt{219}} = 1.0136

This probability is the pvalue of Z when X = 74.2. So

Z = \frac{X - \mu}{s}

Z = \frac{74.2 - 74}{1.0136}

Z = 0.2

Z = 0.2 has a pvalue of 0.5793

0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

5 0
3 years ago
A swimming pool has a diameter of 24 feet. What is the minimum amount of fabric needed to cover the pool if the cover must hang
Alika [10]

Answer:

531.167 ft²

Step-by-step explanation:

Given data

Dimension of pool

Diameter =24ft

Radius =12ft

If the cover must hang by 1ft around, then the diameter is 26ft

Radius =13ft

Area of cover = πr²

Substitute

Area = 3.142*13²

Area =3.143*169

Area =531.167 ft²

Hence the minimum area is 531.167 ft²

5 0
2 years ago
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