The horizontal distance between Carl and the rock at sea is approximately 60.62ft.
Data;
- Angle = 30 degree
- Opposite = 35
- Adjacent = x
<h3>Trigonometric Ratio</h3>
Given the angle of depression from his point to the sea, we can use trigonometric ratio to calculate for the horizontal distance from his location to the bottom of the sea.
SOHCAHTOA
Since we have the value of angle and opposite and we need to calculate the adjacent side of the right-angle triangle, we can use the tangent of the angle to this effect.
The horizontal distance between Carl and the rock at sea is approximately 60.62ft.
Learn more on trigonometric ratio here;
brainly.com/question/12172664
Answer:
40/71
Step-by-step explanation:
Because 71 is prime so there is no other way to simplify
The diameter splits the circle into 2 equal halves by going through the midpoint of the circle. The two halves are called semicircles.
A= (1/2) b*h
h=3 sqrt3
A= (1/2)*6*3sqrt3
A= 9sqrt3 square inches
You start at the y axis and go down 7 so the coordinate is (0, 7) then you move to the right five spaces from (0, 7) and go up 4 from the spot you moved right 7. This should have a positive slope