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3 years ago

A physics student has a battery and three equal resistors. If she uses all of the

Physics

2 answers:

Soloha48 [4]3 years ago

4 0

Answer:

she can arrange the resistors and battery like a butterfly so that you know.... she can do that

Korvikt [17]3 years ago

3 0

Question: A physics student has a battery and an assortment of resistors. If she uses all of the resistors, how should she arrange them in a circuit to obtain the maximum current flow through the battery and the circuit?

Ans: she should arrange them in parallel

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How do electromagnetic waves affect you?

makvit [3.9K]

Answer:

The main effect of radiofrequency electromagnetic fields is heating of body tissues.

Explanation:

Image result for How do electromagnetic waves affect you?

At low frequencies, external electric and magnetic fields induce small circulating currents within the body. ... The main effect of radiofrequency electromagnetic fields is heating of body tissues. There is no doubt that short-term exposure to very high levels of electromagnetic fields can be harmful to health.

7 0

3 years ago

Read 2 more answers

The magnitude of the tidal force between the International Space Station (ISS) and a nearby astronaut on a spacewalk is approxim

vovikov84 [41]

Answer:

F = 4.47 10⁻⁶ N

Explanation:

The expression they give for the strength of the tide is

F = 2 G m M a / r³

Where G has a value of 6.67 10⁻¹¹ N m² / kg² and M which is the mass of the Earth is worth 5.98 10²⁴ kg

They ask us to perform the calculation

F = 2 6.67 10⁻¹¹ 135 5.98 10²⁴ 13 / (6.79 10⁶)³

F = 4.47 10⁻⁶ N

This force is directed in the single line at the astronaut's mass centers and the space station

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3 years ago

A 104.328-kg baserunner slides into home base. He starts his slide moving at 8.451 m/s and 6.596 m from home base; when he cross

JulijaS [17]

The coefficient of kinetic friction between the baserunner and the ground is 0.51.

<h3>Coefficient of kinetic friction </h3>

The coefficient of kinetic friction between the base runner and the ground is calculated as follows;

μ = a/g

where;

a is acceleration
g is gravity

v² = u² + 2as

a = (v² - u²)/(2s)

a = (8.451² - 2.322²)/(2 x 6.596)

a = 5 m/s²

μ = 5/9.8

μ = 0.51

Thus, the coefficient of kinetic friction between the baserunner and the ground is 0.51.

Learn more about coefficient of friction here: brainly.com/question/14121363

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2 years ago

An infinitely long line of charge has a linear charge density of 7.50×10^−12 C/m . A proton is at distance 14.5 cm from the line

Nata [24]

Answer:

10.22 cm

Explanation:

linear charge density, λ = 7.5 x 10^-12 C/m

distance from line, r = 14.5 cm = 0.145 m

initial speed, u = 3000 m/s

final speed, v = 0 m/s

charge on proton, q = 1.6 x 10^-19 C

mass of proton, m = 1.67 x 10^-27 kg

Let the closest distance of proton is r'.

The potential due t a line charge at a distance r' is given by

$V=-2K\lambda ln\left (\frac{r'}{r} \right )$

where, K = 9 x 10^9 Nm^2/C^2

W = q V

By use of work energy theorem

Work = change in kinetic energy

$qV = 0.5m(u^{2}-v^{2})$

By substituting the values, we get

$V=\frac{mu^{2}}{2q}$

$-2K\lambda ln\left ( \frac{r'}{r} \right )=\frac{mu^{2}}{2q}$

$- ln\left ( \frac{r'}{r} \right )=\frac{mu^{2}}{4Kq\lambda }$

$- ln\left ( \frac{r'}{r} \right )=\frac{1.67 \times 10^{-27}\times 3000\times 3000}{4\times 9\times 10^{9}\times 1.6\times 10^{-19}\times 7.5\times 10^{-12} }$