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To determine the velocity of the roller coaster as it moves down, we use the kinematic equation which is expressed as 2gy = vf^2 - v0^2 where g is the gravitational acceleration, y is the elevation of the roller coaster, vf and vo are the final and initial velocity. We calculate as follows:
2gy = vf^2 - v0^2
Since it starts at rest, v0 is zero.
2gy = vf^2
vf = √2gy
vf = √2(9.8)(101)
vf = 44.5 m/s
Answer:
One 200 is bigger than 100
Explanation:
Use the displacement law, peak wavelength = 0.0029/T =0.0029/30000 = 97nm
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