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Ghella [55]
3 years ago
14

State the factor that affect the gravitational force​

Physics
2 answers:
Over [174]3 years ago
5 0

Answer:

<em>The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects.</em>

slamgirl [31]3 years ago
4 0

Answer:Mass and distance are the two factors that affect the gravitational force between any two objects.

mark me as brainliest please

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Astronomers have seen stars forming within a nebular cloud. As the nebular cloud condenses and its own gravitational attraction
Alenkasestr [34]
Nebular cloud should be the answer, but i believe nuclear fusion is the closest answer, because it fuses together to become a cloud 

hope this helps
3 0
4 years ago
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explain " you can not apply a force to an object with out that object applying the same force back to you"​
stealth61 [152]

Answer:

Newton's Third Law Of Motion

Explanation:

3 0
3 years ago
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A well-insulated bucket of negligible heat capacity contains 129 g of ice at 0°C.
Luba_88 [7]

Answer:

The final equilibrium temperature of the system is T = 12.48^oC

For the ice it would melt completely the mass that would remain is Zero

Explanation:

In the following question we are provided with

Mass of the ice M_{i} = 129 g = 0.129 kg

Mass of the steam M_s = 19 g = 0.019 kg

Initial temperature is  T_i = 0°C

Temperature of  steam  T_s = 100°C

Following the change of state of water in the question

 The energy required by ice to change to water is mathematically given as

          Q_A = M_iL_f

Where L_f is a constant known as heat of fusion  and the value is 334*10^3 J/kg

           Q_A = 0.129 *334 *10^3  = 43086 J

The energy been released when the steam changes to water is mathematically given as

            Q_B = M_s * L_v

           Where L_v is a constant known as heat of vaporization and the value is 2256*10^3J/kg

           Q_B = 0.019 * 2256*10^3 = 42864J

         The energy released when the temperature of water decrease from 100°C to 0°C is

                 Q_C = M_s *C_water (100°C)

Where C_{water} is the specific heat of water which has a value 4186J/kg \cdot K

                  Q_C = 0.019 *4186*100 = 7953.4

Looking at the values we obtained we noticed that ]

             Q_B + Q_C > Q_A

What this means is that the ice will melt

bearing in mind the conservation of energy

     looking the way at which water at different temperature were mixed according to the question

     Heat lossed by the vapor   = heat gained by ice

        Q_B + M_s *C_{water}(100-T) = Q_A + M_i C_{water} T

                                               T = \frac{Q_B+M_s *C_{water}(100^oC)-Q_A}{(M_s *C_{water})+(M_i*C_{water})}

                                               T = \frac{42864+7953.4-43086}{(0.019+0.129)(4186)}

                                              T = 12.48^oC

       

3 0
4 years ago
PLEASE HELP!!!
crimeas [40]

Answer: potential to kinetic/mechanical

Explanation:

5 0
3 years ago
Suatu gas memiliki volume 2 m³ dipanaskan dengan kondisi isobarik sehingga volumenya menjadi 5,5 m³ jika tekanan 4 atmosfer hitu
Ivan

Answer:

Sorry if wrong.............

5 0
3 years ago
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