The work dine should br like 4x the amount it stared as
Answer:
voltage across = 1.6 V
Explanation:
given data
resistance R = 57.61 Ω
capacitance c = 13.13 mF = 13.13 ×
F
inductance L = 196.03 mH = 0.19603 H
fixed rms output Vrms = 23.86 V
to find out
voltage across circuit
solution
we know resonant frequency that is
resonant frequency = 1 / ( 2π√(LC)
put the value
resonant frequency = 1 / ( 2π√(0.19603×13.13 ×)
resonant frequency f = 3.1370 HZ
so current will be at this resonant is
current = Vrms / R
current = 23.86 / 57.61
current = 0.4141 A
and
so voltage across will be
voltage across = current / ( 2π f C )
voltage across = 0.4141 / ( 2π ( 3.1370) 13.13 × )
voltage across = 1.6 V
Answer:
The associated SI unit of force and weight is the Newton, with 1 kilogram weighing 9.8 Newtons under standard conditions on the Earth's surface. However, in the US common units, the pound is the unit of force (and therefore weight). The pound is the widely used unit for commerce.
Answer:
Explanation:
If we let our reference frame travel at 30 m/s with the constant speed car, The accelerating car increases its velocity by 10 m/s in 3 seconds.
The average velocity of the accelerating car is (0 + 10) / 2 = 5 m/s
It will advance its position 5 m/s(3 s) = 15 m in the accelerating period.
It takes 5 + 3 = 8 m for the two cars to become side by side.
It would take another 5 + 3 = 8 m for the accelerating car to leave a gap of 3 m between.
The car requires 8 + 8 = 16 m to pass the other safely but the acceleration period only gets him to 15 m.
So despite your saying this is not a YES / NO question, the answer is NO the acceleration is too low or not long enough to meet the required clearances.
Input needed is 10000 J/s / 0.30 = 333333 = J/s
three hours requires 333333(3)(3600) = 360 MJ of energy
360 MJ / 34 MJ/liter = 10.6 liters.
Answer:
50
Explanation:
The mechanical advantage of a machine is given by
where
is the output force
is the input force
For the crowbar in this problem,
is the force in input applied by the worker
is the force that the machine must apply in output to overcome the resistance of the window and to open it
Substituting into the equation, we find
