Answer:
Explanation:
From the conservation of mechanical energy
Solve to velocity v2
Answer:
-32.5 * 10^-5 J
Explanation:
The potential energy of this system of charges is;
Ue = kq1q2/r
Where;
k is the Coulumb's constant
q1 and q2 are the magnitudes of the charges
r is the distance of separation between the charges
Substituting values;
Ue = 9.0×10^9 N⋅m2/C2 * 5.5 x 10^-8 C *( -2.3 x10^-8) C/(3.5 * 10^-2)
Ue= -32.5 * 10^-5 J
Answer:
option D is correct
Explanation:
It is important to note that equipotential lines are always perpendicular to electric field lines. No work is required to move a charge along an equipotential, since ΔV = 0. Thus the work is :
W = −ΔPE = −qΔV = 0.
Work is zero if force is perpendicular to motion. Force is in the same direction as E, so that motion along an equipotential must be perpendicular to E. More precisely, work is related to the electric field by:
W = Fd cos θ = qEd cos θ = 0.
- The change in kinetic energy Δ K.E by conservation should be:
Δ K.E = W
Since, W = 0:
Δ K.E = 0
- If change in kinetic energy is zero it means that charge moves at a constant speed. Hence, option D is correct.
If the polarity of a magnet is flipped while its strength remains constant. There is no change in the electromagnetic force since there is no change in the current in the wire.
<h3>What is the faraday law of electromagnetic induction?</h3>
According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the flow of the amount of current.
If a magnet's polarity were switched while maintaining the same magnetic field intensity. There is no change in the electromagnetic force, and there is no change in the current in the wire.
Hence the current in the wire will be the same as in the first part.
To learn more about the electromagnetic induction refer to:
brainly.com/question/26334813
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