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Ede4ka [16]
3 years ago
11

How can you tell that a precipitate has formed?

Chemistry
2 answers:
ladessa [460]3 years ago
7 0

Answer:

if a solid appears when mixing two liquids

Explanation:

i remember this question :D

Damm [24]3 years ago
6 0
^basically what they said
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Longitudinal waves. In a longitudinal wave the particles in the medium move parallel  to the direction waves go. A good example can be the p-waves in an earthquake.
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Which statement accurately describe the two animals?
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Which element would have properties most like ca (calcium)?
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The element that would have properties most like calcium (ca) is


Beryllium (Be)

Magnesium (Mg)

Strontium (Sr)

Barium (Ba)


This are elements in group two in the periodic table. They are also known as Alkaline earth metals. They have an oxidation state of 2+ since they have two valence electrons in their outermost energy levels.


7 0
3 years ago
Gr6_Sci_Assesment\FY18
Rzqust [24]

Answer:

A. The student did not include the effect of friction in his calculation.

Explanation:

They are not equal because kinetic energy is relative to the state of other objects in its environment such as friction which doesn't apply to potential energy.

5 0
3 years ago
32. A chemical reaction in which calcium carbonate CaCO3 is decomposed, results in the
pantera1 [17]

Answer:

Mass of calcium carbonate decompose 49g.

Explanation:

Given data:

Mass of CaO = 28.00 g

Mass of CO₂ = 21.97 g

Mass of calcium carbonate decompose = ?

Solution:

Chemical equation:

CaCO₃     →    CO₂ + CaO

Number of moles of  CO₂:

Number of moles = mass/molar mass

Number of moles = 21.97 g / 44 g/mol

Number of moles = 0.49 mol

Number of moles of  CaO:

Number of moles = mass/molar mass

Number of moles = 28.00 g / 56.1 g/mol

Number of moles = 0.49 mol

Now we will compare the moles of CaCO₃ with CaO and CO₂ .

                                CO₂                 :           CaCO₃

                                   1                    :             1

                                 0.49                :            0.49

                                 CaO                :           CaCO₃  

                                    1                    :             1

                                  0.49                :            0.49

Mass of CaCO₃ decompose:

Mass = number of moles × molaer mass

Mass = 0.49 mol × 100.1 g/mol

Mass = 49 g

7 0
3 years ago
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