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2 years ago

Please help 25 points and brainlist if you get it right.

Mathematics

1 answer:

Zolol [24]2 years ago

6 0

Answer:

x=14

m<1 = 5×14

= 70°

m<2 = 14 +6

= 20

Step-by-step explanation:

angle 1 + angle 2 = 90°

5x +(x+6) = 90

6(x+1) = 90

x+1 = 90/6

x = 15 - 1

x = 14

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PLEASE HELP ASAP ILL GIVE BRAINLIEST

ICE Princess25 [194]

it’s a because you need all those figures to make it happen

3 0

3 years ago

The _____ justifies the conclusion that ∆ABD ≅ ∆AEC.

elena55 [62]

It is the AAS Postulate.

Explanation: You’re given two right angles (because perpendicular sides make right angles).

This also means that the angle next to them are also right angles, because they are linear pairs (180-90=90)

The right angles are:
This is your first A.

Both triangles also share a similar angle:
This is your second A.

You’re given side BD is congruent to EC.

This is your S.

It’s AAS and not ASA because the order refers to how they are connected: they are congruent in the order that the first set of congruent angles connect to the next, then to the congruent side.

3 0

3 years ago

Mon wants to make 5 lbs of the sugar syrup. How much water and how much sugar does he need to make 75% syrup?

Julli [10]

Answer:

He needs 3.75 lbs of sugar and 1.25 lbs of water.

Step-by-step explanation:

Let x lbs be the amount of sugar in the syrup. Then 5-x lbs is the amount of water in this syrup.

Note

5 lbs - 100%

x lbs - 75%

Write a proportion:

$\dfrac{5}{x}=\dfrac{100}{75}$

Cross multiply:

$100x=5\cdot 75\\ \\100x=375\\ \\x=\dfrac{375}{100}=3.75$

So, he needs 3.75 lbs of sugar and 5 - 3.75 = 1.25 lbs of water.

7 0

3 years ago

A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective

Inessa05 [86]

Answer:

(a) P(X $\leq$ 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

$P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....$

where, n = number of samples taken = 150

r = number of success

p = probability of success which in our question is % of bulbs that

are defective, i.e. 10%

Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.

So, Let X = No. of defective bulbs in a box

Mean of X, $\mu$ = $n \times p$ = $150 \times 0.10$ = 15

Standard deviation of X, $\sigma$ = $\sqrt{np(1-p)}$ = $\sqrt{150 \times 0.10 \times (1-0.10)}$ = 3.7

So, X ~ N( $\mu = 15, \sigma^{2} = 3.7^{2})$

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X $\leq$ 20) = P(X < 20.5) ---- using continuity correction

P(X < 20.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{20.5-15}{3.7}$ ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = $n \times p$ = $150 \times 0.10$ = 15.

5 0

3 years ago

Please help asap I'm not sure how much time I have

BlackZzzverrR [31]

Tan 37,4 = opposite/adjacent

tan 37,4 = x/12,8
• then multiply both sides by 12,8

12,8tan 37,4 = x
Therefore x = 9, 79 x 100
= 97, 86
= 100
( I guess that’s how you can round it to the nearest hundred, please correct me if I’m wrong)

Second one:

8 0

3 years ago