Question

How many grams of aluminum metal can be produced when 50.0 grams of aluminum chloride decompose? 2AlCl3 → 2Al + 3Cl2

Answer 1

Answer:

10.1 g of Al are formed

Explanation:

The reaction is:

2AlCl3 --> 2Al + 3Cl2

So 2 moles of aluminun chloride decompose into 2 moles of Al and 3 moles of chlorine.

Ratio is 2:2.

Let's convert the mass of salt into moles (mass / molar mass)

50 g / 133.34 g/mol = 0.374 moles.

As the ratio is 2: 2, if I have 0.374 moles of salt, I would produce the same amount of Al, just 0.374.

Let's convert the moles to mass

(Mol . molar mass)

0.374 mol . 26.98 g / mol = 10.1 g of Al are formed

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