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Answer:
3.79 moles
Explanation:
To convert moles to gams of a substance we need to find the molar mass of the substance. For Ca(OH)₂ th molar mass is:
1Ca = 40.08g/mol
2O = 2*16g/mol = 32g/mol
2H = 2*1.01g/mol = 2.02g/mol
The molar mass is:
40.08g/mol + 32g/mol + 2.02g/mol = <em>74.1g/mol</em>
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And moles are:
281g * (1mol / 74.1g) =
<h3>3.79 moles</h3>
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the answers is cacih2
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Answer: 1.
2. 3 moles of
: 2 moles of ![Al](https://tex.z-dn.net/?f=Al)
3. 0.33 moles of
: 0.92 moles of ![Al](https://tex.z-dn.net/?f=Al)
4.
is the limiting reagent and
is the excess reagent.
5. Theoretical yield of
is 29.3 g
Explanation:
To calculate the moles :
![\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%7D%20CuCl_2%3D%5Cfrac%7B45.0g%7D%7B134g%2Fmol%7D%3D0.33moles)
The balanced chemical equation is:
According to stoichiometry :
3 moles of
require = 2 moles of
Thus 0.33 moles of
will require=
of
Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 3 moles of
give = 2 moles of
Thus 0.33 moles of
give =
of
Theoretical yield of
Thus 29.3 g of aluminium chloride is formed.