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3 years ago

How many more oxygen atoms are in Na2HPO4H(disodium phosphate) then in 2H3PO(Phosphoric Acid)?

Chemistry

2 answers:

Serggg [28]3 years ago

3 0

Answer:

in disodium phosphate = 4 oxygen atoms

in phosphoric acid = 1 oxygen atom

Ann [662]3 years ago

3 0

Answer: There are 3 more oxygen atoms in Na2HPO4H than 2H3PO

Explanation:

There are 4 oxygen atoms in Na2HPO4H and 1 in 2H3PO. You subtract 4 - 1 =3

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Many portable gas heaters and grills use propane, C3H8(g). Using enthalpies of formation, calculate the quantity of heat produce

Elodia [21]

Answer: 600 kJ

Explanation:

C₃H₈ (g) + 5 O₂ (g) =============== 3 CO₂ (g) + 4 H₂O (l)

Δ⁰Hf kJ/mol -104 0 -393.5 -285.8

Δ⁰Hcomb C₃H₈ = 3(-393.5) + 4 (-285.80) - (-104) kJ/mol

Δ⁰Hcomb = 2219.70 kJ/mol

n= m /MW MW c₃H₈ = 44.1 g/mol

n= 12 g/44.1 g/mol = 0.27 mol

then for 12 g the heat released will be

0.27 mol x 2219.70 kJ/mol = 600 KJ

4 0

3 years ago

Read 2 more answers

The motion of atoms and molecules that most affects temperature is

Oliga [24]

A solid to a liquid, the boiling of water, solid the water molecules vibrate condensed but as a liquid they are still isolated in a controlled area and also reflect off one another more, liquid to a gas they do not and move freely until condensation occurs

3 0

3 years ago

If the amount of Adams if each type on the left and right sides of a reaction difference what must be done to balance it

Ivanshal [37]

Hey there,

Your answer would be

Coefficients are placed in front of the reactants and/or products

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<h2>- <em>Mr. Helpful</em></h2>

8 0

3 years ago

Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH

Doss [256]

Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{12 g}{60 g/mol}$

= 0.2 mol

Molarity of acetic acid is calculated as follows.

Density = $\frac{mass}{volume}$

1 g/ml = $\frac{100 g}{volume}$

volume = 100 ml

Hence, molarity = $\frac{\text{no. of moles}}{volume}$

= $\frac{0.2 mol}{0.1 L}$

= 2 mol/l

As reaction equation for the given reaction is as follows.

$NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O$

So, moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

$x \times 1 M = 10 mL \times 2 M$ (as 1 L = 1000 ml)

x = 20 L

Thus, we can conclude that volume of NaOH required is 20 ml.

6 0

3 years ago

A patient needs to be given exactly 1000 ml of a 5.0% (w/v) intravenous glucose solution. the stock solution is 55% (w/v). how m

LiRa [457]

The patient needs 1000 ml of 5% (w/v) glucose solution
i.e 1000 ml x 5 g/ 100 ml
where the stock solution is 55% (w/v) = 55 g / 100 ml
So, 1000 ml x 5 g / 100 ml = V (ml) x 55 g / 100 ml
V = 1000 x (5 / 100) / (55 / 100) = 5000 / 55 = 90.9 ml
∴ the patient needs 90.9 ml of 55% (w/v) glucose solution

6 0

3 years ago