Answer:
Is this the full question
Explanation:
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Answer:
127°C
Explanation:
This excersise can be solved, with the Charles Gay Lussac law, where the pressure of the gas is modified according to absolute T°.
We convert our value to K → -73°C + 273 = 200 K
The moles are the same, and the volume is also the same:
P₁ / T₁ = P₂ / T₂
But the pressure is doubled so: P₁ / T₁ = 2P₁ / T₂
P₁ / 200K = 2P₁ / T₂
1 /2OOK = (2P₁ / T₂) / P₁
See how's P₁ term is cancelled.
200K⁻¹ = 2/ T₂
T₂ = 2 / 200K⁻¹ → 400K
We convert the T° to C → 400 K - 273 = 127°C
Answer: 1.15x10²³ molecules C
Explanation: solution attached:
Convert mass of C to moles using its molar mass then multiply to the Avogadro's number.
Answer:
2,780,000mg
Explanation:
Using the Metric Staircase photo provided, you can calculate how many mg there are in 2.78 kg by simply moving the decimal point six places to the right, since the "Kilo" step takes six places to move to the "Milli" step.
2.78 kg
---------------
2 7 8 0 0 0 0 .
we can see that the decimal point is moved to the right six places.
Answer:
2,780,000mg
C. 25 Miles
This is because you have 12.5 moles of water and using the ratio this is 2 (molar ratio). Therefore the molar ratio for HF is 4, so 12.5 x 2 = 25 moles