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faust18 [17]
3 years ago
12

Convert 100 ml to L can you help mee??

Chemistry
2 answers:
Vladimir79 [104]3 years ago
6 0

Answer:

0.1  L

Explanation:

divide the volume value by 1000

raketka [301]3 years ago
4 0

Answer:

0.1 L that is the answer

Explanation:

I searched it

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Calcium Carbide (CaC2) is an unusual substance that contains a carbon anion (C2 2- ). The reaction with water involves several s
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The question is incomplete. The complete question is:

Calcium Carbide (CaC₂) is an unusual substance that contains a carbon anion (C₂²⁻). The reaction with water involves several steps that occur in rapid succession. CaC2 is a salt (notice that its name is similar to sodium chloride). When a salt dissolves in water, ions leave the crystal lattice and enter the aqueous (aq) solution. Write the relevant balanced chemical equation for the dissolution of CaC₂, in water.

Answer:

CaC₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + C₂H₂(aq)

Explanation:

When a salt dissolves in water, it dissociates in its ions. In the Calcium Carbide, the cation is Ca⁺² and the anion is C₂²⁻, so the reaction is:

CaC₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + C₂H₂(aq)

The base Ca(OH)₂ is soluble, so it will dissociate at Ca⁺ and OH⁻, but the C₂H₂ is stable and doesn't dissociate in the solution.

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2 years ago
During the combustion of methane (CH4), one mole of methane gas combines with two moles of oxygen gas (O2) to produce one mole o
astraxan [27]

Answer:

CH4(g) +2O2____ CO2(g) +2H2O (l)

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Explain the difference between weathering and erosion.
yanalaym [24]

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6 0
2 years ago
a water sample is found to have a cl- content of 100ppm as nacl what is the concentration of chloride in moles per liter
ladessa [460]

Answer:

The concentration of chloride ion is 2.82\times10^{-3}\;mol/L

Explanation:

We know that 1 ppm is equal to 1 mg/L.

So, the Cl^- content 100 ppm suggests the presence of 100 mg of Cl^- in 1 L of solution.

The molar mass of Cl^- is equal to the molar mass of Cl atom as the mass of the excess electron in Cl^- is negligible as compared to the mass of Cl atom.

So, the molar mass of Cl^- is 35.453 g/mol.

Number of moles = (Mass)/(Molar mass)

Hence, the number of moles (N) of Cl^- present in 100 mg (0.100 g) of Cl^- is calculated as shown below:

N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol

So, there is 2.82\times10^{-3}\;mol of Cl^- present in 1 L of solution.

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