Ask question

Ask question

All categories

3 years ago

12

Convert 100 ml to L can you help mee??

2 answers:

Vladimir79 [104]3 years ago

6 0

Answer:

0.1 L

Explanation:

divide the volume value by 1000

raketka [301]3 years ago

4 0

Answer:

0.1 L that is the answer

Explanation:

I searched it

You might be interested in

One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/K

mina [271]

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy ( $s_{2} - s_{1}$ ), in joules per gram-Kelvin, by the following model:

$s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }$

$s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }$

$s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}}$ (1)

Where:

$m$ - Mass, in kilograms.

$c_{w}$ - Specific heat of water, in joules per kilogram-Kelvin.

$T_{1}$ , $T_{2}$ - Initial and final temperatures of water, in Kelvin.

If we know that $m = 1\,kg$ , $c_{w} = 4190\,\frac{J}{kg\cdot K}$ , $T_{1} = 373.15\,K$ and $T_{2} = 288.15\,K$ , then the change in entropy for the entire process is:

$s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}$

$s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}$

The change in entropy is -1083.112 joules per kilogram-Kelvin.

7 0

3 years ago

What forms when iron-53 decays?

amm1812

It depends on the type of decay that is taking place if its a β+ it will decay into Mn-52 β- decays into Co-59

3 0

4 years ago

Read 2 more answers

How many moles of NaOH are there in 3 mL of 9.0M NaOH?

Mademuasel [1]

Answer:

0.027mol

Explanation:

9M NaOH tells us that there is 9 mol of NaOH per L of NaOH

converting 3mL to L = 0.003L

0.003L * 9 mol/L = 0.027mol

5 0

3 years ago

A cylinder contains water to a level of 15.5. 20.0 grams of copper is dropped in. What will be the new height of the water? (Den

Julli [10]

The new height of the water is 17.7 mL

The density of a substance is simply defined as mass per unit volume of the substance. Mathematically, it is expressed as:

<h3>Density = mass / volume </h3>

With the above formula, we can obtain the volume of the copper. This can be obtained as follow:

Mass of copper = 20 g

Density of copper = 8.96 g/mL

<h3>Volume of copper =?</h3>

Density = mass / volume

8.96 = 20 / volume

Cross multiply

8.96 × Volume = 20

Divide both side by 8.96

Volume = 20 / 8.96

<h3>Volume of copper = 2.2 mL</h3>

Finally, we shall determine the new height of the water. This can be obtained as follow:

Initial height of water = 15.5 mL

Volume of copper = 2.2 mL

<h3>New height of water =?</h3>

<h3>New height of water = (Initial height of water) + (Volume of copper)</h3>

New height of water = 15.5 + 2.2

<h3>New height of water = 17.7 mL</h3>

Therefore, the new height of the water is 17.7 mL

Learn more: brainly.com/question/24679715

7 0

3 years ago

Rank these acids according to their expected pKa values.ClCH2COOHClCH2CH2COOHCH3CH2COOHCl2CHCOOHIn order of highest pka to lowes

Ilia_Sergeevich [38]

Answer:

CH₃CH₂CH₂COOH > CH₃CH₂COOH > ClCH₂CH₂COOH > ClCH₂COOH

Explanation:

Electron-withdrawing groups (EWGs) increase acidity by inductive removal of electrons from the carboxyl group.

Electron-donating groups (EDGs) decrease acidity by inductive donation of electrons to the carboxyl group.

The closer the substituent is to the carboxyl group, the greater is its effect.
The more substituents, the greater the effect.
The effect tails off rapidly and is almost zero after about three C-C bonds.

CH₃CH₂-CH₂COOH — EDG — weakest — pKₐ = 4.82

CH₃-CH₂COOH — reference — pKₐ = 4.75

ClCH₂-CH₂COOH — EWG on β-carbon— stronger — pKₐ = 4.00

ClCH₂COOH — EWG on α-carbon — strongest — pKₐ = 2.87

6 0

3 years ago

Read 2 more answers