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Finger [1]
2 years ago
11

Richard is buying hamburgers. He can buy 5 hamburgers for $6.20 or 12 hamburgers for $14.88. Which equation represents the cost,

y, of
x hamburgers?
A. y = 1.20x

B. X = 1.20y
C. y = 1.24x
D. X = 1.24y
Mathematics
1 answer:
weeeeeb [17]2 years ago
6 0
D. X=1.24y



divide $6.20 by 5 and get 1.24, you can also do 14.88 divided by 12 and get 1.24.
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grigory [225]
r=10\cos\theta\implies r^2=10r\cos\theta\implies x^2+y^2=10x
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What is the volume of the cube below?
vladimir2022 [97]

Answer:

wht cube

Step-by-step explanation:

7 0
3 years ago
You have$560 in an account which pays 4.8% compounded annually. If you invest your money for 8 years, then how many dollars of i
SCORPION-xisa [38]

Answer:

$ 254.85

Step-by-step explanation:

Total amount invested = $ 560

Interest rate = r = 4.8% = 0.048

Time in years = t = 8 years

The formula for compound interest is:

A =P(1+\frac{r}{n})^{nt}

Here,

A is the total amount accumulated after t years. P is the amount invested initially and n is the compounding periods per year. Since in this case compounding is done annually, n will be 1. Using the values in the above formula, we get:

A=560(1+\frac{0.048}{1})^{8} = \$ 814.85

Thus, the total amount accumulated after 8 years will be $ 814.85

The amount of interest earned will be:

Interest = Amount Accumulated - Principal Amount

Interest = $ 814.85 - $ 560 = $ 254.85

By the end of 8 years, $ 254.85 would be earned in interest.

7 0
3 years ago
I rlly need help with this :(
kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 72.6, \sigma = 2.7.

Item a:

The percentile is the <u>p-value of Z when X = 74.2</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{74.2 - 72.6}{2.7}

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:

X = 78:

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 72.6}{2.7}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 72.6}{2.7}

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
.01xn=3.792<br> please help me
brilliants [131]
X=379.2/n
N=379.2/x
I hope that helps
4 0
3 years ago
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