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postnew [5]
3 years ago
10

A sample of pure iron has a mass of 5.00g. What's the calculation of its volume??? Please help me or my moms gonna freak

Chemistry
1 answer:
GarryVolchara [31]3 years ago
5 0
Since the iron is pure, we can look up its density value online and will always be true. This density value of iron is 7.87g/L. Now, we can use the density formula (D = m/V) and rearrange it to solve for V. This new equation is then V = m/D. Next, we plug in our known values and solve for V (5.00g/7.87g/L). This gives us our final answer of 0.635L (three sig figs due to the three sig figs in the provided mass).

Hope this helps!
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The steps required to prepare 200.0 mL of an aqueous solution of iron (III) chloride, at a concentration of 1.25x10^-2 M. Please
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Answer:

In order to prepare 200.0 mL of an aqueous solution of iron (III) chloride, at a concentration of 1.25 x 10⁻² M, you need to weight 0.4055 g of FeCl₃ and add to 200.0 mL of water.

Explanation:

Concentration: 1.25 x 10⁻² M

1,25 x 10⁻² mol FeCl₃ ___ 1000 mL

              x                   ___ 200.0 mL

         x = 2.5 x 10⁻³ mol FeCl₃

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1 mol FeCl₃ _____________ 162.2 g

2.5 x 10⁻³ mol FeCl₃ _______    y

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8 0
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Hope this helps, if not, comment below please!!!

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