I got false. But worthier answer is right.
Solving this using the time, we know that range = horizontal velocity x time of flight
<span>since there are no horizontal forces acting on the ball, there are no horizontal accelerations and the initial horizontal velocity of 36 cos 28 will be constant throughout. I</span><span>f we use the correct time of flight given the launch parameters, we have </span>
<span>range = 36 cos 28 x 3.44 s = 109.3 m </span>
Answer:
(a) 58 cm
(b) 591.4 Hz
(c) 246.5 cm
Explanation:
(a)
For closed organ pipe, the wavelength is given by
where 
is wavelength, L is the length of the pipe and n is the resonance
Substituting 217.5 m for L and 8 for n then the wavelength of the sound will be
(b)
We know that the speed of sound, v is a product of frequency and wavelength.
Making frequency the subject of the formula then
and since the velocity is given as 343 m/s and wavelength is already found in part a above but now we change units from cm to m then
(c)
We know that
The next resonance will be the 9th and we know the wavelength hence making L the subject then
