All categories

3 years ago

An individual who is monitoring one’s goal-achieving behavior is demonstrating which phase of the self-regulation cycle?

Physics

2 answers:

poizon [28]3 years ago

8 0

Answer:

c. forethought

Explanation:

a was wrong so im guessing its c

galina1969 [7]3 years ago

4 0

Answer:

1. A 2. C yes

Explanation:

yeeeeeeeeeeeeeereeeesssssssas

You might be interested in

6. A large balloon containing 2.00×103 m3 of helium gas at 1.00 atm and a temperature 15.0◦ C rises rapidly from ground level to

RideAnS [48]

Answer:

2130 m³, 3.11 °C, 1.25×10⁷ J

Explanation:

No heat is exchanged, so this is an adiabatic process. For an ideal gas, this means:

PV^((f+2)/f) = constant,

where P is pressure, V is volume, and f is degrees of freedom.

For a monatomic gas, f=3. For a diatomic gas, f=5. Since helium is monatomic, f=3.

Therefore:

PV^(5/3) = PV^(5/3)

(1.00 atm) (2.00×10³ m³)^(5/3) = (0.900 atm) V^(5/3)

V = 2130 m³

For an ideal gas in an adiabatic process, we can also say:

VT^(f/2) = constant

Therefore:

(2.00×10³ m³) (15.0 + 273.15 K)^(3/2) = (2130 m³) T^(3/2)

T = 276.26 K

T = 3.11 °C

Finally, the change in internal energy is:

ΔU = (f/2) nRΔT

We need to find the number of moles, n, using ideal gas law:

PV = nRT

n = PV/(RT)

n = (1.00 atm) (2.00×10³ m³) / ((8.21×10⁻⁵ atm m³ / mol / K) (15.0 + 273.15 K))

n = 84,500 mol

So the change in internal energy is:

ΔU = (3/2) (84,500 mol) (8.314 J/mol/K) (15.0 - 3.11) K

ΔU = 1.25×10⁷ J

6 0

3 years ago

Can someone please help me!!!!!

aksik [14]

Answer:

Converted to wave pulses

Explanation:

Hope it helps you

3 0

3 years ago

What are the properties of bungee gum,hmmm?

lys-0071 [83]

It’s both a solid and a liquid. It can thicken and soften depending on how it’s handled. It can be used to cover wounds to stop bleed, and used to drown enemies. Bungee Gum has the properties of both rubber and gum.

8 0

3 years ago

Read 2 more answers

A person hums into the top of a well and finds that standing waves are established at frequencies of 140, 196, and 252 Hz. The f

Mars2501 [29]

Answer:

Depth of well 3.06m

Explanation:

We know that for a pipe closed at one end the frequencies are in ratios if 1:2:3:5:7.... to the fundamental frequency

In our case the given frequencies are in the ratio of

a) $\frac{140}{196}=\frac{5}{7}$

b) $\frac{196}{252}=\frac{7}{9}$

Thus the fundamental frequency can be calculated as $140Hz=5n$

$\therefore n=\frac{140}{5}=28Hz$

Now we know that

$\lambda_{1}=4l\\\\\frac{v}{f}=4l\\\\l=\frac{v}{4f}$

Applying values we get

$L=3.06m$

7 0

4 years ago

The depth of water behind the Hoover Dam is 220 m. Find the water pressure at the base of this dam.

Sav [38]

Pressure under water is called the gauge pressure.
$Pressure= \frac{Force}{Area} \\ F=mg \\ P= \frac{mg}{A}$
Now the next part is difficult to put into an equation because you need the symbol for density, which is ρ, pronounced rho. I cannot type ρ into the equation so I will use p.
$p= \frac{m}{V}$ (m=mass, V=Volume)
$m=pV \\ P= \frac{pVg}{A} \\ V=Ah$
A=Area of the base of the object, or cylinder of water above the object, h= height of object
$P= \frac{p(Ah)g}{A}$
The "A"s cancel, leaving us with
$P=pgh$

You are only looking for the water pressure, so you would not be concerned with atmospheric pressure on top of that.

$P_{gauge} =p_{liquid} g h_{object}$

The density of water is $1000 \frac{kg}{ m^{3} }$
Use 1000 for ρ
Gravity is 9.8
Height is 220

$P=pgh \\ P=1000*9.8*220 \\ P=2.16*10^{6} Pa$
(Pa is Pascals, the unit for pressure)

6 0

3 years ago