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salantis [7]
3 years ago
5

What is the density of hydrogen sulfide at 1.1 atm and 304K?

Chemistry
1 answer:
Daniel [21]3 years ago
6 0

Use equation:  

PV = nRT  

1.4*V = 1*0.082057*332  

V = 27.24/1.4  

V = 19.46L  

Molar mass H2S = 2+32 = 34g/mol  

34g H2S has volume 19.46L  

Density = mass / volume = 34/19.46 = 1.75 g/L

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What challenges would you encounter with the titration if you had used apple cider vinegar or balsamic vinegar as the analyte in
Vika [28.1K]

Explanation:

Apple cider vinegar or balsamic vinegar might contain various synthetics which might  interact with or nullified the findings, whereas white vinegar comprises of acidic acid only. In fact, apple cider vinegar and balsamic vinegar are deep in appearance this would make it very difficult to determine the color. This is why it is preferable to use white vinegar in the Titration process.

3 0
3 years ago
3. longitude is measured in degrees, hours, and seconds. a. true b. false
katen-ka-za [31]
Degrees true     hours false      seconds false
3 0
3 years ago
PLEASE HELP!?Consumers must eat other organisms for energy. Which organisms are consumers in this food chain?
Vitek1552 [10]

Answer:

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4 0
2 years ago
A chef plans to mix 100% vinegar with italian dressing. the italian dressing contains 13% vinegar. the chef wants to make 150 mi
charle [14.2K]
To determine the volume of both concentration of vinegar, we need to set up two equations since we have two unknowns. 

For the first equation, we do a mass balance:

mass of 100% vinegar + mass of 13% vinegar = mass of 42% vinegar

Assuming they have the same densities, then we can write this equation in terms of volume.

V(100%) + V(13%) = V(42%)
   we let x = V(100%)
             y = V(13%)

x + y = 150

For the second equation, we do a component balance:

1.00x + .13y = 150(.42)
x + .13y = 63

The two equations are
x + y = 150
x + .13y = 63

Solving for x and y,
x = 50
y = 100

Therefore, you need to mix 50 mL of the 100% vinegar and 100 mL of the 13% vinegar.

6 0
3 years ago
What is the molarity of a 17.0% by mass solution of sodium acetate, NaC2H3O2 (82.0 g/mol), in water? The density of the solution
sattari [20]

Answer:

[NaCH₃COO] = 2.26M

Explanation:

17% by mass is a sort of concentration. Gives the information about grams of solute in 100 g of solution. (In this case, 17 g of NaCH₃COO)

Let's determine the volume of solution, by density

Mass of solution / Volume of solution = Solution density

100 g / Volume of solution = 1.09 g/mL

100 g / 1.09 g/mL = 91.7 mL

17 grams of solute is contained in 91.7 mL

Molarity (M) = Mol of solute /L of solution

91.7 mL / 1000 = 0.0917L

17 g / 82 g/m = 0.207 moles

Molariy = 0.207 moles / 0.0917L → 2.26M

4 0
3 years ago
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