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salantis [7]
2 years ago
5

What is the density of hydrogen sulfide at 1.1 atm and 304K?

Chemistry
1 answer:
Daniel [21]2 years ago
6 0

Use equation:  

PV = nRT  

1.4*V = 1*0.082057*332  

V = 27.24/1.4  

V = 19.46L  

Molar mass H2S = 2+32 = 34g/mol  

34g H2S has volume 19.46L  

Density = mass / volume = 34/19.46 = 1.75 g/L

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In the SI system of units, the mole is one of seven base units. It is frequently used in chemical calculations. However, a mole
Irina-Kira [14]

Answer

Do you think that the mole should be considered a base unit in the SI system?

The mole is not a base unit on a par with the six property base units; it cannot be used in significant physical–chemical comparisons until the subscript parameter p in mole-of-Ep has been given a certain “value”."

Explanation:

5 0
2 years ago
Write the correct chemical formula for potassium and sulfur
Shalnov [3]
Phosphorus + Sulfur ------> Phosphorus sulfide

2P + 3S ------> P2S3


Hope it helped!
3 0
3 years ago
A gas sample occupies 200 mL at 760 mm Hg. What volume does the gas occupy at 400 mm Hg?
astra-53 [7]

Answer:

201.9

Explanation:

when you divided 760 with 400 yo get 19.0 the add it with 200 you get that answer

3 0
3 years ago
Be sure to answer all parts. this is a two-part question. first, draw the minor alkene product that should be formed in the reac
kotykmax [81]

Answer:

See explanation below

Explanation:

The question is incomplete, however, I found a question very similar to this, and I'm assuming this is the question you are asking to answer. If it's not, please tell me which one it is. Here's a tip for you to get an idea of how to solve.

Picture 1, would be the original question. Picture 2 is the answer of it.

Now, This is a E1 reaction where this type of reactions are taking place in two steps. The first step is the formation of the carbon cation, this step is always slow. The secon step is the addition of a nucleophyle, or, in this case, formation of a pi bond, and we get a alkene.

Hope this can help you

8 0
2 years ago
1. The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percen
Naddik [55]

Answer:

72.8 % (But verify explanation).

Explanation:

Hello,

In this case, with the following obtained results, the percent error is computed as follows:

Volume of vinegar= 7.0 mL

Volume of NaOH= (7+6.6+6.4)/3= 6.7 mL

Used concentration of NaOH= 1.5M

Concentration of acetic acid= (concentration of NaOH*volume of NaOH)/volume of vinegar= (6.7mL*1.5M)/7.0M= 1.44M

Assuming we have 100 mL (0.100L) of vinegar, moles of acetic acid in vinegar = 1.44M x 0.100 L= 0.144 mol

Mass of acetic acid in 100g of vinegar = 0.144 mol x 60.0g/mol= 8.64 g

% of acetic acid in vinegar=8.64 %

% error in percentage of acetic acid = [(8.64% - 5.0%)/5.0] x 100=72.8 %

Clearly, this result depend on your own measurements, anyway, you can change any value wherever you need it.

Regards.

8 0
3 years ago
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