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Rainbow [258]
2 years ago
13

when 1 mol of glucose is burned, 2802.5kj of energy is released. calculate rhe quantity of energy released to a person by eating

5.00g of glucose in a candy
Chemistry
1 answer:
tester [92]2 years ago
8 0

77.78 kJ of energy is released when 1 mol of glucose is burned, 2802.5 kJ of energy is released.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 ×10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Calculate the moles of 5.00g of glucose.

Given mass = 5.00g

The molar mass of glucose = 180.156 g/mol

Moles = \frac{mass}{molar \;mass}

Moles = \frac{5.00g}{180.156 g/mol}

Moles =0.02775372455

The quantity of energy released to a person by eating 5.00g of glucose in a candy.

0.02775372455 x 2802.5 kJ

77.77981305 kJ =77.78 kJ

Hence, 777.78 kJ of energy is released.

Learn more about moles here:

brainly.com/question/8455949

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No, iron is not

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2 moles of substance A contains 12.04 × 1023 atoms.
professor190 [17]

Answer:

2 moles of Substance B

Explanation:

Because 1 mole of any substance contains 6.02× 10²³ particles either atoms, molecules, ions or even electron(Avogardo Constant)

Therefore 12.04 × 10²³/ 6.02× 10²³  =  2 mole of Substance B

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imagine you are a particle of air explain your journey in the atmosphere as you beacome a heated particle if you answer it clear
enyata [817]
Well when a particle of air is becomes heated it rises, right? So you could write some like you started off close to the earth (aka the troposphere) until you became heated then you started to rise and as you reached higher elevations you cooled down and you were recycled into cool air and you moved back down and became new fresh cool air until the next time you'll become heated and rise again to be recycled into fresh cool new air.
6 0
3 years ago
If a gas has a proportionality constant of 4.32 x 10-4 mol at room temperature for a particular solvent, what will the
inysia [295]

0.0467 X 10^{-4} M/kPa is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

<h3>What is Henry's law?</h3>

Mathematically, we can get this from Henry's law

From Henry law;

Concentration = Henry constant × partial pressure

Thus Henry constant = \frac{Concentration}{partial \;pressure}

Henry constant = \frac{4.32 \;X \;10^{-4} mol}{92.4kPa}

= 0.0467 X 10^{-4} M/kPa

Hence, 0.0467 X 10^{-4} M/kPa is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

Learn more about the Henry's law here:

brainly.com/question/16222358

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6 0
1 year ago
How many molecules are contained in 125 grams of water, H20?
sergejj [24]
Answer:

18,01528

Explanation:
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Read 2 more answers
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