The solution would be like
this for this specific problem:
<span>25.0 g CCl4 x (1 mole CCl4
/ 153.8 g CCl4) = 0.163 moles CCl4
</span>(29.82 kJ / mole)(0.163 moles) = 4.86 kJ
total heat = 1.11 kJ + 4.86 kJ = 5.97 kJ
<span>I hope this helps and if you have
any further questions, please don’t hesitate to ask again. </span>
No, if H2O is separated into H2 and O, then it is not the same substance
Answer: 15.1 grams
Given reaction:
Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3
Mass of Na2CO3 = 20.0 g
Molar mass of Na2CO3 = 105.985 g/mol
# moles of Na2CO3 = 20/105.985 = 0.1887 moles
Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH
# moles of NaOH produced = 0.1887*2 = 0.3774 moles
Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol
Mass of NaOH produced = 0.3774*39.996 = 15.09 grams
Explanation:
<span>
</span><span> average reaction rate </span><span>= change in concentration / change in time
by putting values we have
= (1.00M - 0.987M) / (4.00s - 0.00s)
= 3.25x10^-3 mol/Lsec
this is our conclusion
hope this helps</span>
I think it is c because food and clothing aren't technically chemicals however they do contain them so d is a possible answer but I think it is c
