Let "a" and "b" be some number where:
a - b = 24
We want to find where a^2 + b^2 is a minimum. Instead of just logically figuring out that the answer is where a=b=12, I'll just use derivatives.
So we can first substitute for "a" where a = b+24
So we have (b+24)^2 + b^2 = b^2 +48b +576 + b^2
And that equals 2b^2 +48b +576
Then we take the derivative and set it equal to zero:
4b +48 = 0
4(b+12) = 0
b + 12 = 0
b = -12
Thus "a" must equal 12.
So:
a = 12
b = -12
And the sum of those two numbers squared is (12)^2 + (-12)^2 = 144 + 144 = 288.
The smallest sum is 288.
Answer:
18.7 mph
Step-by-step explanation:
768.57m / 41.1h = 18.7 mph
Let's see -
Follow the directions below to get your answer -
0.75 × 68 = 51
51 + 68 = 119
So, 119 is your answer
68 increased by 75% is 119.
↑ ↑ ↑ Hope this helps! :D
It would look like this: O=C=O
Hope this helps you out.
Divide each side of the equation by 18. Then it will say 'm = a fraction'.
That's the solution. You can reduce (simplify) the fraction to make it look
neater.
