The grams of potassium chlorate that are required to produce 160 g of oxygen is 408.29 grams
<u><em>calculation</em></u>
2 KClO₃→ 2 KCl + 3O₂
Step 1: find the moles of O₂
moles = mass÷ molar mass
from periodic table the molar mass of O₂ = 16 x2 = 32 g/mol
moles = 160 g÷ 32 g/mol = 5 moles
Step2 : use the mole ratio to determine the moles of KClO₃
from equation given KClO₃ : O₂ is 2:3
therefore the v moles of KClO₃ = 5 moles x 2/3 = 3.333 moles
Step 3: find the mass of KClO₃
mass= moles x molar mass
from periodic table the molar mass of KClO₃
= 39 + 35.5 + (16 x3) =122.5 g/mol
mass = 3.333 moles x 122.5 g/mol =408.29 grams
Answer:
-195.8º < -191.5º < 100º
Explanation:
Water, or H20, starts boiling at 100ºC.
Nitrogen, or N2, starts boiling at -195.8ºC.
Carbon monoxide, or C0, starts boiling at -191.5ºC.
When we place these in order from decreasing boiling point:
-195.8º goes first, then -191.5º, and 100º goes last.
A mixture that results when substances dissolve to form a homogeneous mixture is a solution.
Answer:
1.05 mol
Explanation:
Step 1: Given data
- Molarity of sulfuric acid (M): 1.325 M (1.325 mol/L)
- Volume of solution (V): 395 mL (0.395 L)
Step 2: Calculate the moles of sulfuric acid (n)
We will use the following expression.
M = n/V
n = M × V
n = 1.325 mol/L × 0.395 L = 0.523 mol
Step 3: Calculate the moles of H⁺
H₂SO₄ dissociates completely according to the following equation.
H₂SO₄ ⇒ 2 H⁺ + SO₄²⁻
The molar ratio of H₂SO₄ to H⁺ is 1:2. The moles of H⁺ are 2/1 × 0.523 mol = 1.05 mol.
The amount of Calcium hydroxide : = 58.719 g
<h3>Further explanation</h3>
Given
100 g Nitric Acid-HNO₃
Required
The amount of Calcium hydroxide
Solution
Reaction(balanced) :
Ca(OH)₂ (s) + 2HNO₃ (aq) → Ca(NO₃)₂ (aq) + 2H₂O (l)
mol of Nitric acid (MW 63 g/mol) :
mol = mass : MW
mol = 100 : 63
mol = 1.587
From the equation, mol ratio of Ca(OH)₂ : HNO₃ = 1 : 2, so mol Ca(OH)₂ :
=1/2 x mol HNO₃
= 1/2 x 1.587
=0.7935
Mass of Ca(OH)₂ (MW=74 g/mol) :
= mol x MW
= 0.7935 x 74
= 58.719 g
