A. wavelength
wavelength is the distance between 2 crests of a wave
Answer:
The nswer to the question is
The maximum fraction of the air in the room that could be displaced by the gaseous nitrogen is 0.548 or 54.8 %
Explanation:
To solve the question we note that
The density of the liquid nitrogen = 0.808g/mL and the volume is 195 L tank (vaporised)
Therefore since density = mass/volume we have
mass = Density × volume = 0.808 g/mL × 195 L × 1000 ml/L =157560 g
In gaseous form the liquid nitrogen density =1.15 g/L
That is density = mass/volume and volume = mass/density = 157560 g/(1.15g/L) or
volume = 137008.69565 L
The dimension of the room = 10 m × 10 m × 2.5 m = 250 m³ and
1 m³ is equivalent to 1000 L, therefore 250 m³ = 250 m³ × 1000 L/m³ = 250000L
Therefore fraction of the volume occupied by the gaseous nitrogen =
137008.69565 L/250000 L = 0.548
Therefore the gaseous nitrogen occpies 54.8% of the room
Answer:
To supply the required ions it is necessary to inject 5,6mL of 6g/30mL solution and 131,1 mL of 0,9% solution.
Explanation:
1mEq of sodium are 59mg of NaCl and 1mEq of potassium are 75mg KCl
in intravenous infusion 15 mEq of K are:
15x75mg KCl = 1,125g of KCl
And 20 mEq of Na are:
20x59mg NaCl = 1,18g of NaCl
To supply the potassium ion it is necessary to inject:
1,125g of KCl×
=<em> 5,6mL of 6g/30mL solution</em>
And, to supply the sodium ion it is necessary to inject:
1,18g of NaCl×
= <em>131,1 mL of 0,9% solution</em>
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I hope it helps!
At constant temperature, if the pressure is compressed to the given value, the volume of the nitrogen gas increases to 23.2L.
<h3>What is Boyle's law?</h3>
Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
Boyle's law is expressed as;
P₁V₁ = P₂V₂
Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.
Given that;
- Initial volume of the gas V₁ = 22.5L
- Initial pressure of the gas P₁ = 0.98atm
- Final pressure of the gas P₂ = 0.95atm
- Final volume of the gas V₂ = ?
P₁V₁ = P₂V₂
V₂ = P₁V₁ / P₂
V₂ = (0.98atm × 22.5L) / 0.95atm
V₂ = 22.05Latm / 0.95atm
V₂ = 23.2L
Therefore, at constant temperature, if the pressure is compressed to the given value, the volume of the nitrogen gas increases to 23.2L.
Learn more about Boyle's law here: brainly.com/question/1437490
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