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Alexxx [7]
3 years ago
6

A solution is prepared by dissolving 7.14 g KClO in 318 g of water. What is the molality of this solution? You do not need to sh

ow work!
Chemistry
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

im not that sure but i think 2.7132

Explanation:

change the 7.14g to litres and change 318g to litres

then use 7.14/318 ( after changing the numbers )

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Chemists investigated an unknown substance and found it to have the following characteristics:
bija089 [108]

The answer is option C.

That is it is a heterogeneous mixture.

Heterogeneous mixture have the following properties:

1. Different components could be observed in the substance.

2. Different samples of the substance appeared to have different proportions of the components.

3.The components could be easily separated using filters and sorting.


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4 years ago
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It would be nice if someone HELPED. During an experiment, you observe that two charged balloons repel each other. When you bring
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They are similarly charged, which is why they repel each other.

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5. What type of clouds can be found in the mesosphere?
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Some material from meteors lingers in the mesosphere, causing this layer to have a relatively high concentration of iron and other metal atoms. Very strange, high altitude clouds called "noctilucent clouds" or "polar mesospheric clouds" sometime form in the mesosphere near the poles.

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8 0
3 years ago
A scientist digs up sample of arctic ice that is 458,000 years old. He takes it to his lab and finds that it contains 1.675 gram
Fiesta28 [93]

Answer:

6.70 grams of krypton-81 was present when the ice first formed

Explanation:

Let use the below formula to find the amount of sample

N= N_0(\frac{1}{2})^n

where

n = \frac{t}{t_{\frac{1}{2}}}

here

t =  458,000 years

t_{\frac{1}{2}} = 229,000

\frac{t}{t_{\frac{1}{2}}} = \\frac{ 458,000}{229,000}

n = \frac{t}{t_{\frac{1}{2}}} = 2.000

Now substituting the values

1.675 = N_0(\frac{1}{2})^{2.000}}

1.675 = N_0\times (0.2500)

N_0= \frac{1.675}{0.2500}

N_0=6.70

3 0
3 years ago
How many mL will a 0.205 mole sample of He occupy at 3.00 atm and 200 K? Report your answer to the nearest mL.
Tcecarenko [31]

1.1214 mL will a 0.205-mole sample of He occupy at 3.00 atm and 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.00 atm

V= ?

n=0.205 mole

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=200 K

Putting value in the given equation:

\frac{nRT}{P} =V

V= \frac{0.205 \;mole\;0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 200}{3 \;atm}

V= 1.1214 mL

Learn more about the ideal gas here:

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4 0
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