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alekssr [168]
3 years ago
15

Is this adjacent, linear pair, vertical, or none?

Mathematics
1 answer:
Dmitrij [34]3 years ago
3 0

Answer and Step-by-step explanation:

None of the options listed.

This line is called a <u>transversal line</u>. This is because it goes through two or more (in this case, 2) lines at an angle. Transversal lines intersect a system of lines.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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URGENT I NEED HELP!!!!!!!!!!!!!!!!!!!!
Nataliya [291]

Answer:

$11

Step-by-step explanation:

66/6=11

3 0
3 years ago
A total of 769 tickets were sold were for the play.Thwy were either adult tickets or students tickets.There were 69 more student
aleksandrvk [35]

Answer:

  350 adult tickets were sold

Step-by-step explanation:

Let "a" represent the number of adult tickets sold. Then the number of student tickets is (a+69) and the total number of tickets sold is ...

  a + (a+69) = 769

  2a = 700 . . . . . . . . subtract 69

  a = 350 . . . . . . . . . divide by 2

350 adult tickets were sold.

7 0
3 years ago
What is the sum of the first five terms of the geometric sequence in which a1=5 and r=1/5?
Makovka662 [10]
Sum of series of G.P. = Sn = a(1-rⁿ) / 1-r
Here, a = 5
r = 1/5

Substitute their values into the expression:
Sn = 5(1-1/5⁵) / 1 - 1/5
Sn = 5*5/4 [1-1/3125]
Sn = 25/4 [ 3124/3125]
Sn = 781 / 125

In short, Your Answer would be 781/125 in fraction form 
or 6.248 in decimal form

Hope this helps!
3 0
3 years ago
An angle measures 23.4° more than the measure of its complementary angle. What is the measure of each angle?
kodGreya [7K]

Answer:

62°

Step-by-step explanation:

Complementary angles by definition are two or more angles that add up to 90°. So we must do 90°-62° to get the missing angle which is 62°.

Hope that helped.

8 0
3 years ago
Find a recursive formula for the sequence: 1, -1,-7,-25
RoseWind [281]

Check the forward differences:

-1 - 1 = -2

-7 - (-1) = -6

-25 - (-7) = -18

Notice how the differences appear to follow a geometric progression with common ratio 3. So if a_n denotes the nth term in the given sequence, we seem to have

a_2-a_1=-2\cdot3^0

a_3-a_2=-2\cdot3^1

a_4-a_3=-2\cdot3^2

so that the general pattern for n>1 would be

a_n-a_{n-1}=-2\cdot3^{n-2}

Then the sequence is given recursively by

a_n=\begin{cases}1&\text{for }n=1\\a_{n-1}-2\cdot3^{n-2}&\text{for }n>1\end{cases}

The first 10 terms in the sequence would be

1, -1, -7, -25, -79, -241, -727, -2185, -6559, -19681

4 0
4 years ago
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