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3 years ago

Which option is an example of chemical energy being transformed into kinetic

Physics

2 answers:

zysi [14]3 years ago

8 0

Answer: B. A battery powering a flashlight.

Explanation: A P E X

SVEN [57.7K]3 years ago

5 0

D I know this because I know lol.

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PLZ HELP

TEA [102]

Answer:

The ion has more protons than electrons.

Explanation:

6 0

3 years ago

jack be nimble jack be quick jack jumped over the candlestick with a velocity of 5.0 m/s at an angle of 30.0 degrees to horizont

Mrrafil [7]

Answer:

Explanation:

The vertical component of Jack's initial velocity is:

5.0

⋅

sin

∘

5.0

⋅

2.5

m/s

With gravitational acceleration

9.8

m/s

, he will reach the highest point of his trajectory after:

2.5

9.8

≈

0.255

The average vertical component of his velocity in that

0.255

will be:

⋅

2.5

1.25

m/s

So the highest point of his trajectory will be:

0.255

⋅

1.25

≈

0.32

So he will pass approximately

above the top of the candle.

The horizontal component of his velocity will be a constant:

5.0

⋅

cos

∘

5.0

⋅

√

≈

4.33

m/s

So Jack's trajectory will be substantially longer than it is high and he will spend little time anywhere near above the candle.

4 0

3 years ago

Neutrons incident on a heavy nucleus with spin J 0 show a resonance at an incident energy ER = 250 eV in the total cross-section

ivolga24 [154]

Answer:

elastic partial width is 2.49 eV

Explanation:

given data

ER E = 250 eV

spin J = 0

cross-section magnitude σ = 1300 barns

peak P = 20ev

to find out

elastic partial width W

solution

we know here that

σ = λ²× W / ( E × π × P ) ...................1

put here all value

σ = (0.286)² × W × $10^{-16}$ / ( 250 × π × 20 )

1300 × $10^{-24}$ = (0.286)² × W × $10^{-16}$ / ( 250 × π × 20 )

solve it and we get W

W = 249.56 × $10^{-2}$

so elastic partial width is 2.49 eV

8 0

4 years ago

Where did most of the comets in the Kuiper belt come from?

IgorC [24]

Answer:

The answer you would be looking for is A.

Explanation:

6 0

3 years ago

Read 2 more answers

A car is traveling at a speed of 10m/s. A 0.5kg clump of mudis

CaHeK987 [17]

Answer:B

Explanation:

Given

speed of car $v=10 m/s$

mass of clump $m=0.5 kg$

Radius of car tire $r=0.2 m$

Since the tire is rotating about axle so a centripetal force is acting constantly on each particle towards the center of tire.

Centripetal force is given by

$F_c=\frac{mv^2}{r}$

where $m=mass\ of\ element$

$v=speed$

$r=distance\ from\ center$

$F_c=\frac{0.5\times 10^2}{0.2}$

$F_c=250\ N$ (inward)

3 0

4 years ago