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crimeas [40]
4 years ago
15

the strong nuclear force is one which acts only on the ____________ (A) electrons in the electron cloud (B) attraction between a

toms [C] protons and neutrons in the nucleus
Physics
1 answer:
ch4aika [34]4 years ago
7 0
The strong nuclear force is the force that holds nucleons, aka protons and neutrons in the nucleus together, through the boson called the gluon. It also holds quarks together, which constitutes the protons and neutrons.
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Ram jumps onto a cement floor from a height of 1m and comes to rest in 0.1sec.
umka2103 [35]

Answer:

3/10 F.

Explanation:

Height ( h ) = 1m

Time taken ( t ) = 0.1 second

Height² ( h² ) = 9m

Time taken² ( t² ) = 1 second

Solution,

F = ma

= m ( v - u ) / t

= m √2gh / t

now,

F/F² = √h/h² × t/t²

F¹ = 3/10 F.

answer !!

5 0
3 years ago
How can accuracy be limited?
lozanna [386]

Answer:

accuracy refers to the deviation of a measurement from a standard or true value of the quantity being measured

5 0
3 years ago
What does an electromagnet have that a bar magnet does not ?
Anon25 [30]
The bar magnet and the electromagnet act identical. The difference being a electromagnet is a coil of wire that has a power source connect to both ends, this energizes the coil with an electromagnetic field.
4 0
3 years ago
Titus drives his jetski a distance of 1000 meters in 7.045 seconds. How fast was he moving in meters per second? How fast was he
Ksenya-84 [330]

Answer:

a) v = 141.9 m/s

b) v = 317.4 miles/h

Explanation:

a) How fast was he moving in meters per second?

v = \frac{d}{t} = \frac{1000 m}{7.045 s} = 141.9 m/s

Hence, the jet ski is moving at 141.9 meters per second.

b) How fast was he moving in miles per hour?

v = \frac{d}{t} = \frac{1000 m}{7.045 s} = 141.9 m/s*\frac{3600 s}{1 h}*\frac{1 mile}{1609.34 m} = 317.4 miles/h      

Therefore, the jet ski is moving at 317.4 miles per hour.

I hope it helps you!

5 0
3 years ago
Two tractors pull against a 1000 kg log. If the angle of the tractors' chains in relation to each other is 18.0° (each 9.0° from
Morgarella [4.7K]
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