Answer:
Part a)
Part b)
Explanation:
Part a)
As we know that electric field intensity due to some given charge distribution is given as
now electric flux through a spherical surface of radius r is given as
now by Guass law we know that
now volume charge density is given as
Part b)
Total charge inside the radius R is given as
Answer:
Option C is correct.
The magnitude of the field is reduced to half at twice the distance,
Explanation:
The magnetic field produced in a long, straight conductor carrying a current I at distance r is given by
B = μ₀I/2πr
Where μ₀ is the constant permeability of free space.
If we increase the distance by twice then
B = μ₀I/2π(2r)
B = μ₀I/2πr(2)
B = B/2
Therefore, the magnitude of magnetic field is reduced by B/2 at twice the distance.
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.40 as a fraction is 4/10 or 2/5
the 4 is in the tenths place, so put it over a 10 to make it a fraction.
then, simplify the fraction by dividing the numerator and denominator by 2, and you get 2/5
Answer:
C 3.3 s
Explanation:
Given:
Δy = 9 m
v₀ = 0 m/s
a = ⅙ (9.8 m/s²) = 1.63 m/s²
Find: t
Δy = v₀ t + ½ at²
9 m = (0 m/s) t + ½ (1.63 m/s²) t²
t = 3.3 s
