Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation.
To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign.
Pb(s) --> Pb2+ +2e- E0 = +0.13 V
Ag+ + e- ---> Ag E0 = +0.80 V
Adding up the E0's would yield an overall electric cell potential of +0.93 V.
Answer:
True
Explanation:
The more of each substanse that you add to the bag will cause it to produce faster and more gas.
Answer: Both fluorescence and phosphorescence are based on the ability of a substance to absorb light and emit light of a longer wavelength and therefore lower energy. The main difference is the time in which it takes to do so. So if it disappears immediately, it's fluorescence. If it lingers, it's phosphorescence.
Explanation:
Answer:
Explanation: A compound with the empirical formula SO has a molecular weight of 96.13
