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JulijaS [17]
3 years ago
10

1.a)How many types of particles are formed when a strong alkali is dissolved in water??

Chemistry
1 answer:
sveticcg [70]3 years ago
4 0

Answer:

I didn't know how to explane it

but this should help you get your answer

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The maximum oxygen uptake is known as the __________.
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The maximum oxygen uptake is known as the VO2 max.
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You are on a flight to Los Angeles, California. As the plane gets ready to land, it flies out over a large body of water. You lo
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What ocean is next to California on google maps? That is your answer.

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When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
3 years ago
Find the no. Of electron involved in the electro deposition of 63.5g of cu from a solution of cuso4
sp2606 [1]
This is a redox reaction, meaning reduction-oxidation reaction. This represents the reaction in one side of the electrode in an electrolysis set-up. First, we find the oxidation number of Cu in CuSO4:

(ox. # of Cu)+ ox.# of S + 4(ox.# of oxygen) = 0
(ox. # of Cu) + (6) + 4(-2) = 0
ox. # of Cu = 2+

CuSO4 ---> Cu + SO42-
Cu2+ + SO42-  ---->  Cu + SO42-
Cu2+ -----> Cu + 2e-   (net ionic reaction)

The stoichiometric equation would be 2 electrons per mole Copper. Copper has a molar mass of <span>63.5 g/mol. Then, it would only need 2 electrons.


</span>
8 0
3 years ago
(b) Why is nitrogen used for storage of semen<br>in artificial insemination?​
aev [14]
Nitrogen is often used for the storage of semen samples for artificial insemination of cattle. Nitrogen is used to maintain a dry inert atmosphere over chemicals during storage, reaction or processing. Used in brewing, soft drinks and wine-making industries to exclude air from the product and de-aerate water.
3 0
3 years ago
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