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4 years ago

Which is the smallest part of a compound called?

Chemistry

2 answers:

lidiya [134]4 years ago

6 0

The answer is molecule

sineoko [7]4 years ago

3 0

The atom is the smallest part.

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The amount of I−3(aq) in a solution can be determined by titration with a solution containing a known concentration of S2O2−3(aq

Pavlova-9 [17]

Answer : The molarity of $I_3^-$ in the solution is, 0.128 M

Explanation :

The given balanced chemical reaction is,

$2S_2O_2^{-3}(aq)+I_3(aq)\rightarrow S_4O_2^{-6}(aq)+3I^-(aq)$

First we have to calculate the moles of $Na_2S_2O_3$ .

$\text{Moles of }Na_2S_2O_3=\text{Molarity of }Na_2S_2O_3\times \text{Volume of solution}$

$\text{Moles of }Na_2S_2O_3=0.260mole/L\times 0.0296L=0.007696mole$

Conversion used : (1 L = 1000 ml)

Now we have to calculate the moles of $I_3^-$ .

From the balanced chemical reaction, we conclude that

As, 2 moles of $S_2O_2^{-3}$ react with 1 mole of $I_3^-$

So, 0.007696 moles of $S_2O_2^{-3}$ react with $\frac{0.007696}{2}=0.003848$ mole of $I_3^-$

The moles of $I_3^-$ = 0.003848 mole

Now we have to calculate the molarity of $I_3^-$ .

$\text{Molarity of }I_3^-=\frac{\text{Moles of }I_3^-}{\text{Volume of solution}}$

Now put all the given values in this formula, we get:

$\text{Molarity of }I_3^-=\frac{0.003848mole}{0.03L}=0.128mole/L=0.128M$

Therefore, the molarity of $I_3^-$ in the solution is, 0.128 M

8 0

3 years ago

Calculate the change in ph when hcl is added to a buffer solutio that is nh3 and nh4

ki77a [65]

1.) Calculate the change in pH when 4.00 ml of 0.100 M HCl(aq) is added to 0.100 mL of a buffer solution that is 0.100 M in NH3 (aq) and 0.1000 M in NH4Cl(aq).
2.) Calculate the change in pH when 4.00 mL of 0.100 M in NaOH(aq) is added to the original buffer solution.

8 0

3 years ago

Iron has a density of 7.86 g/cm^3 (1 cm^3=1 mL). Calculate the volume (in dL) of a piece of iron having a mass of 4.62 kg . Note

s2008m [1.1K]

Density is mass over volume. The density of iron is given in g/cm³

we have to first convert g/cm³ to kg/dL.

1000 g = 1 kg and 100 cm³ = 1 dL

the mass of 1 cm³ = 1 g

the mass of 100 cm³ / 1 dL = 100 g

then mass of 1 dL in kg is = 100 g / 1000 g/kg = 0.1 kg

volume of 0.1 kg is 1 dL

therefore density of iron is 7.86 g/cm³ x 0.1 kg/dL / g/cm³ = 0.786 kg/dL

volume of iron having mass 0.786 kg is 1 dL

then volume of iron having a mass of 4.62 kg is - 1 dL / 0.786 kg x 4.62 kg = dL

volume of iron is 5.88 dL

3 0

3 years ago

How many joules are required to melt 100 grams of water? The heat of

vova2212 [387]

Answer- 33.4 kJ

Explanation-

100 g H2O x (1mol/18g) = 5.5 mol

q=(5.5 mol)(6.01 KJ/mol)= 33.4 kJ

4 0

3 years ago

What is the density of 10cm^3 volume of water that has a mass of 10g?

prisoha [69]

Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 10 g

volume = 10 cm³

It's density is

$density = \frac{10}{10} = 1 \\$

We have the final answer as

Hope this helps you

3 0

4 years ago

Read 2 more answers