Answer:
Explanation:0.493 M NaOH means 0.493 mol NaOH/L
mols
mols = ------ x L
L
mols = M x V
In a titration procedure, 40.57 mL of 0.493 M NaOH solution was used. How many mols NaOH did this volume of NaOH solution contain?
mols = M x V
0.493 mols NaOH
mols = ----------------------- x 0.04057 L
L
mols = 0.0200 mols NaOH
2 NI₃= N₂ + 3 I₂
2 x 394.71 g --------------- 3 x 253.80 g
3.58 g ---------------------- ( mass of I₂ )
3.58 x 3 x 253.80 / 2 x 394.71 =
2725.812 / 789.42 => 3.4529 g of I₂
1 mole I₂ --------------- 253.80 g
?? ----------------------- 3.4529 g
3.4529 x 1 / 253.80 => 0.0136 moles of I₂
Answer C
hope this helps!
Answer:
1 mole of dinitrogen combined with 3 moles of diiodine yields 2 moles of nitrogen triiodide
Explanation:
Explanation:
Using Beer-Lambert's law :
Formula used :
where,
A = absorbance of solution
c = concentration of solution
l = length of the cell
= molar absorptivity of this solution
According to question:
A = (C) : absorbance measured by the spectrometer
c = (B) : concentration, in mol/L, of the stock solution from which the sample was made
l = (A): pathlength of light through the cell
ε = (D) : molar absorptivity, a constant unique to that substance at that wavelength
