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trapecia [35]
2 years ago
7

Explain the difference between a front and an air mass.

Chemistry
1 answer:
iVinArrow [24]2 years ago
8 0

Answer: The differences is Air masses cover over thousands and hundreds and millions of square kilo. A front is a boundary which two air masses but different temperature and moisture content meet.

Explanation:

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A rigid tank that contains 2 kg of N2 at 25°C and 550 kPa is connected to another rigid tank that contains 4 kg of O2 at 25°C an
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Answer:

The volume in the first tank = 0.32 m^{3}

The volume in the second tank = 2.066 m^{3}

The  final pressure of the mixture = 203.64 K pa

Explanation:

<u>First Tank </u>

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From the ideal gas equation

P V = m R T

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<u>Second tank</u>

Mass =  4 kg

Pressure = 150 K pa

Temperature = 25 °c = 298 K

Gas constant for oxygen = 0.26  \frac{KJ}{Kg K}

From the ideal gas equation

P V = m R T

150 × V = 4 × 0.26 × 298

V = 2.066 m^{3}

This is the volume in the second tank.

This is the iso thermal mixing. i.e.

P_{3} V_{3}  = P_{1} V_{1} + P_{2} V_{2} ----- (1)

V_{3}  = V_{1}  + V_{2}

V_{3}  = 0.32 + 2.066

V_{3}  = 2.386 \ m^{3}

Put this value in equation (1)

P_{3} × 2.386 =  550 × 0.32 + 150 × 2.066

P_{3} = 203.64 K pa

Therefore the  final pressure of the mixture = 203.64 K pa

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