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3 years ago

Please anyone help me

Chemistry

1 answer:

sweet-ann [11.9K]3 years ago

8 0

Answer:

F. a dark solid formed on the zinc.

-Is because when the solid is formed it is called the "precipitate", which is commonly know as chemical reaction.

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Which equation shows how to calculate how many grams (g) of KOH would be needed to fully react with 4 mol Mg(OH)2? The balanced

bazaltina [42]

Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
moles KOH ------------------- 4 moles Mg(OH₂)

moles KOH = 4 x 2 / 1

= 8 moles of KOH

molar mass KOH = 56 g/mol

mass of KOH = n x mm

mass of KOH = 8 x 56

= 448 g of KOH

hope this helps!

3 0

3 years ago

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an unknown sample required 21.05 mL of 0.02047 M KmnO4 to reach the end point. How many moles of KmnO4 reacted?

Angelina_Jolie [31]

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3 years ago

An atom of element A has 108 protons. What would the elements atomic number be?

marusya05 [52]

108 is the atomic number

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3 years ago

How many particles are in 47.7 g of Magnesium? (Round the average

Lynna [10]

Answer:

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

47.7 g Mg

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

Step 3: Convert

$47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} )$ = 1.18161 × 10²⁴ particles Mg

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

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3 years ago

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dusya [7]

Answer:

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Explanation:

we know that helium is a pure substance although helium atoms are sometimes mixed with their isotopes it is still the same element. since there is no other element combined with helium this makes it an element.

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3 years ago