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nataly862011 [7]
2 years ago
7

What is meant by the statement ' protential difference between point A and Point B in an electric circuit is 1 V' ?​

Chemistry
1 answer:
liubo4ka [24]2 years ago
7 0

Answer:

The potential difference is considered as the change in terms of voltage or Del V. It is measured in terms of voltage so that statement got the name voltage change between point A & B is 1. It means that I joule of work is carried out for moving the 1 coulomb of charge from the point A to B.

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Calculate the molality of a solution that is prepared by mixing 25.5 ml of ch3oh (d = 0.792 g/ml and 387 ml of ch3ch2ch2oh (d =
Zanzabum
The solvent is <span>ch3ch2ch2oh with a volume of 387 mL which is equivalent to
387 mL (0.811 g/mL) (1 kg /1000 kg) = 0.3139 kg
The moles of the alchol is
25.5 mL (0.792 g/mL) (1 mol/32 g) = 0.631 mol
The molality is
0.631 mol / 0.3139 kg = 2.01 mol/kg</span>
8 0
3 years ago
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You will need the Gas Law:

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3 years ago
Which balanced equation represents a redox reaction?
nlexa [21]

Answer: option (3) CuO + CO ⇄ Cu + CO₂


Explanation:


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2) An oxidation-reduction reaction is one in which at least one species is oxidized and other (or others) is reduced.


3) Oxidation is the increase on the oxidation number, which occurs by releasing electrons.


4) Reduction is the decrease of the oxidation number, which occurs by gaining electrons.


5) By looking at the oxidation numbers of the reactants and the products you can tell whether a reaction is a redox one.


6) There are some rules to calculate the oxidation states which you need to handle to determine the oxidation states of the atoms in any chemical formula.


7) The main rule that you can use at a glance is if an element is alone in one side of the equation and is bonded to other kind of atom in the other side.


That is because the rule states that for any element that is not combined with other element its oxidation state is 0.


In this case, you can apply that rule to the equation of the choice number (3). In that, you can see that Cu is pure which as per the mentioned rule means that its oxidation state is 0.


As Cu is combined with O, CuO, in the reactant side of the chemical equation, then its oxidation number is not 0. Indeed, the rule is that in the formula CuO the oxidation states of Cu and O add up 0, and since the oxidation number of O is 2-, the oxidation number of Cu is 2+.


Therefore, having Cu changed its oxidation state from 2+ to 0, it was reduced, and this is a redox reaction.


Of course other atoms had to be oxidized. It was C whose oxidation state went from 2+ in CO to 4+ in CO₂.

7 0
2 years ago
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What is the point of doing an experiment. Help thank you​
bogdanovich [222]

Answer:

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3 years ago
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The rungs of a DNA ladder are made up of NITROGEN BASES 
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