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2 years ago

Hjgkhbmhjmhjzdsj,zdzkjfls.

Chemistry

2 answers:

attashe74 [19]2 years ago

8 0

Don’t nobody know what that means . Djehdhsjs

Darya [45]2 years ago

3 0

What does that mean.

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The taste of sour milk is lactic acid. What is the molecular formula for lactic acid if the percent composition is 40.00% C, 6.7

Svetradugi [14.3K]

Answer:

C3H6O3

Explanation:

To find the emperical of the compound,you divide the percentage composition of each element by it's molar mass(C=12, H=1, O=16).

For C,40/12=3.33. For H,6.71/1=6.71

For O,53.19/16=3.33.

Then divide everything by the smallest value which is 3.33

For C,3.33/3.33=1. For H,6.71/3.33=~2.

For O,3.33/3.33=1.

Emperical formula=CH2O

Molecular formula=(CH2O)n=90

(12+2*1+16)n=90

30n=90, n=3

molecular formula=(CH2O)3

molecular formula of lactic acid=C3H6O3.

4 0

3 years ago

Convert 300c into kelvin and Fahrenheit scale

Nitella [24]

Explanation:

300c = 1.8f+32= please calculate it yourself ☺

300c= k+273= 573k

5 0

3 years ago

Is it possible to find density and volume of a substance with just the mass?

tensa zangetsu [6.8K]

Even though an atom may be smaller than another atom, it might have more mass. The mass of atoms, their size, and how they are arranged determine the density of a substance. Density equals the mass of the object divided by its volume; D = m/v. Objects with the same mass but different volume have different densities.

7 0

2 years ago

Difference between fission and fusion?

algol13

The difference is the following: Fission is when a heavy nucleus is very unstable and is splitted into two lighter nuclei. Fusion is in a sense the contrary process: two light nuclei combine and release more energy

4 0

3 years ago

Theoretically, what mass of [Co(NH3)4(H2O)2]Cl2 could be produced from 4.00 g of CoCl2•6H2O starting material. If 1.20 g of [Co(

Romashka [77]

<u>Answer:</u> The theoretical yield and percent yield of $[Co(NH_3)_4(H_2O)_2]Cl_2$ is 3.93 g and 30.53 % respectively

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $CoCl_2.6H_2O$ = 4.00 g

Molar mass of $CoCl_2.6H_2O$ = 238 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CoCl_2.6H_2O=\frac{4.00g}{238g/mol}=0.0168mol$

The chemical equation for the reaction of $CoCl_2.6H_2O$ to form $[Co(NH_3)_4(H_2O)_2]Cl_2$ follows:

$CoCl_2.6H_2O+4NH_3\rightarrow [Co(NH_3)_4(H_2O)_2]Cl_2+4H_2O$

By Stoichiometry of the reaction:

1 mole of $CoCl_2.6H_2O$ produces 1 mole of $[Co(NH_3)_4(H_2O)_2]Cl_2$

So, 0.0168 moles of $CoCl_2.6H_2O$ will produce = $\frac{1}{1}\times 0.0168=0.0168mol$ of $[Co(NH_3)_4(H_2O)_2]Cl_2$

Now, calculating the mass of $[Co(NH_3)_4(H_2O)_2]Cl_2$ from equation 1, we get:

Molar mass of $[Co(NH_3)_4(H_2O)_2]Cl_2$ = 234 g/mol

Moles of $[Co(NH_3)_4(H_2O)_2]Cl_2$ = 0.0168 moles

Putting values in equation 1, we get:

$0.0168mol=\frac{\text{Mass of }[Co(NH_3)_4(H_2O)_2]Cl_2}{234g/mol}\\\\\text{Mass of }[Co(NH_3)_4(H_2O)_2]Cl_2=(0.0168mol\times 234g/mol)=3.93g$

To calculate the percentage yield of $[Co(NH_3)_4(H_2O)_2]Cl_2$ , we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of $[Co(NH_3)_4(H_2O)_2]Cl_2$ = 1.20 g

Theoretical yield of $[Co(NH_3)_4(H_2O)_2]Cl_2$ = 3.93 g

Putting values in above equation, we get:

$\%\text{ yield of }[Co(NH_3)_4(H_2O)_2]Cl_2=\frac{1.20g}{3.93g}\times 100\\\\\% \text{yield of }[Co(NH_3)_4(H_2O)_2]Cl_2=30.53\%$

Hence, the theoretical yield and percent yield of $[Co(NH_3)_4(H_2O)_2]Cl_2$ is 3.93 g and 30.53 % respectively

6 0

2 years ago