14 = - 2x + 8
2x = - 6
x = - 3
To find it, evaluate it at the endpoints and the vertex
in form
f(x)=ax²+bx+c
the x value of the vertex is -b/2a
given
c(t)=1t²-10t+76
x value of vertex is -(-10)/1=10
evaluate c(0) and c(13) and c(10)
c(0)=76
c(13)=115
c(10)=76
it reached minimum in 2000 and 2010
porbably teacher wants 2010
the min value is $76
Answer:
No solutions
Step-by-step explanation:
Isolate the absolute value:
|x−1| + 5 = 2
Subtract 5 from both sides:
|x-1| = -3
Since an absolute value can never be equal to a negative number, there are no solutions.
Answer:
c.
Step-by-step explanation:
If its isoceles, then LM is equal to LN. This means 3x-2 = 2x+1. 3x minus 2x is x. 2 plus 1 is 3. So x = 3. So it needs to be c or d. since LM and LN are the same answers, go to MN and find the answer. If you siubstitute 3 for x in 5x-2, then you get 13.
