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I am Lyosha [343]
2 years ago
15

Slope = 3/2, y-intercept = 0

Mathematics
2 answers:
Feliz [49]2 years ago
8 0

what's the question?

spayn [35]2 years ago
4 0

the answer is y=3/2+0

Step-by-step explanation:

the equation for the answer is y=mx+b m repusents slope and the y-intercept repusents b i hope this helps you out.

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In the figure above, the measure of <BDE is 20 and CD is perpendicular to DE. What is the measure of <ADC ?​
notsponge [240]

Answer:

∠ ADC = 110°

Step-by-step explanation:

∠ CDE = 90° ( angle between perpendicular lines ) , then

∠ CDB + ∠ BDE = 90°

∠ CDB + 20° = 90° ( subtract 20° from both sides )

∠ CDB = 70°

∠ ADC and ∠ CDB are adjacent angles on a straight line and sum to 180° , so

∠ ADC + ∠ CDB = 180° , that is

∠ ADC + 70° = 180° ( subtract 70° from both sides )

∠ ADC = 110°

6 0
2 years ago
Let x △ y be defined by x △ y=x−5y. What is the value of 3 △  (−4)
TEA [102]

x\Delta y=x-5y\\\\3\Delta(-4)\qquad\text{put the values x = 3 and y = -4 to the expression x - 5y}:\\\\3\Delta(-4)=3-5(-4)=3+20=23

5 0
3 years ago
Which two of the following is continuous data?
Alla [95]

Answer:

B. Age of student

D. Time taken to run 1 mile

Step-by-step explanation:

From the list of given options, only B and D satisfy the required condition.

One unique determinant of continuous data is that; they are measured and not counted.

Now, let's categorize option A to D into two

1. Counted data

2. Measured data

Options that fall into the category of measured data are said to be continuous data.

A. Concert attendance; The number of people in a concert is counted

B. The age of a student is measured (in years)

C. Number of pens in a box is counted

D. Time taken to run 1 mile is measured (in units like seconds, minutes, hours, etc...)

In summary; we have

Counted

A. Concert Attendance

C. Number of pens in a box

Measured

B. Age of a student

D. Time taken to run 1 mile

Hence, the continuous data are Age of a student and Time taken to run 1 mile

7 0
3 years ago
Sandra's scores on the first 4 tests were 87%, 92%, 76%,and 89%. What is the minimum score she needs to make on the fifth test s
sergejj [24]

Answer:

Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.

Step-by-step explanation:

Given:

First 4 test scores = 87%, 92%, 76%,89%

Average targeted = 80%

We need to find the minimum score she needs to make on fifth test to achieve average of at least 80%.

Solution:

Let the minimum score she needs to make in fifth test be 'x'.

Total number of test = 5

Now we know that;

Average is equal to sum of all the scores in the test divided by number of test.

framing in equation form we get;

\frac{87+92+76+89+x}{5}=80

Multiplying both side by 5 we get;

\frac{344+x}{5}\times 5=80\times 5\\\\344+x=400

Subtracting both side by 344 we get;

344+x-344=400-344\\\\x=56\%

Hence Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.

5 0
3 years ago
Explain how knowing 50×4 = 200 helps you find 500 times 400.
skad [1K]

it equals to 200,000


4 0
3 years ago
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