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IrinaK [193]
3 years ago
8

Three capacitors with individual capacitances of 2 μF, 5 μF, and 10 μF

Physics
1 answer:
rodikova [14]3 years ago
5 0

Answer:

1.25C

Explanation:

When capacitance is in series we add them like this: 1/Ctotal = 1/C1 +1/C2 + 1/C3.....

1/C = 1/2 + 1/5 + 1/10 = 5 + 2 + 1/10 = 8/10

C = 10/8 = 1.25

Capacitance = Charge/potential difference(Q/V)

1.25 = Charge/12

Total charge = 1.25 ×12 =15coulombs

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