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olganol [36]
3 years ago
11

Which of the following statements is true regarding the use of refrigerants?

Physics
2 answers:
Damm [24]3 years ago
5 0
B.

Refrigerants should be handled using approved equipment only.
Mandarinka [93]3 years ago
4 0
<h2>Use of Refrigerant - Option B </h2>

Recover and recycle refrigerant using epa-approved equipment. Refrigerants must be examined by utilizing just guaranteed material. A refrigerant is a thing or blend which is generally a liquid that utilized in a warmth pump and preservation period.

In most periods, it supports phase transformations from a liquid to a gas and repeated. Several moving liquids have been utilized for such goals.

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A skateboarder is accelerating forward. How would his acceleration change if he had more mass?
exis [7]

Answer:

If the force remains the same, the acceleration would decrease

Explanation:

According to Newton's second law, the acceleration of an object is given by

a=\frac{F}{m}

where

F is the force applied to the object

m is the mass of the object

As we see from the formula, the acceleration a is inversely proportional to the mass, m. Therefore, if the force F remains constant, this means that if the mass of the skateboarder increases, then the acceleration will decrease.

4 0
3 years ago
1. The string shown is 1.5 meters long and is vibrating as the first harmonic. The string vibrates up and down with 33 cycles in
svet-max [94.6K]

Answer:

Explanation:

ok

6 0
2 years ago
A new pest is found that only feeds on corn plant leaves. Which promoter would you choose if the modified gene produces toxins t
8090 [49]

It is actually B. Promoter 2.

Your welcome

Say safe

5 0
3 years ago
A textbook of mass 2.05 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose d
blsea [12.9K]

Answer:

a. 7.38 N b. 40.87 N c. 0.113 kg-m²

Explanation:

a. Let T be the tension in the cord. For the textbook, T = ma since no other force acts on it and it is an horizontal force, and m = mass = 2.05 kg and a = acceleration. We find the acceleration from s = ut + 1/2at² where u = initial speed = 0 (since it starts from rest),  s = distance moved = 1.30 m and t = time = 0.850 s.

Substituting these values into s,

1.30 m = 0 × 0.850 + 1/2a × 0.850² = 0 + 0.36125a

1.30 = 0.36125a

a = 1.30/0.36125 = 3.6 m/s²

Substituting this into T, we have

T = ma = 2.05 kg × 3.6 m/s² = 7.38 N

b.  Let T be the tension in the cord attached to the book. The book has the only vertical forces acting on it as the tension, T(acting upwards) and its weight mg (acting downwards). So the net force acting on it is

T - mg = ma

T = m(a + g)

substituting a = 3.6 m/s² and g = 9.8 m/s² and m = 3.05 kg

T = 3.05(3.6 + 9.8) = 3.05 × 13.4 = 40.87 N

c. Since the tangential acceleration of the pulley is also the acceleration of the masses, the a = rα where r = radius of pulley = 0.200 m/2 = 0.100 m and α = angular acceleration of the pulley.

α = a/r = 3.6 m/s² ÷ 0.100 m = 36 rad/s²

Now, the torque on the pulley τ = Tr = Iα where I = moment of inertia of pulley about its rotational axis and T = tension in cord attached to book and r = radius of pulley = 0.200 m/2 = 0.100 m

From the equation above, I = Tr/α

Substituting the variables we have

I = 40.87 N × 0.100 m ÷ 36 rad/s² = 0.113 kg-m²

4 0
3 years ago
Read 2 more answers
A ball is fixed to the end of a string, which is attached to the ceiling at point P. As the drawing shows, the ball is projected
Ganezh [65]

Answer:

The ball's initial kinetic energy

The ball comes to a stop at B. At this point its initial kinetic energy is converted into potential energy

Explanation:

A ball is fixed to the end of a string, which is attached to the ceiling at point P. As the drawing shows, the ball is projected downward at A with the launch speed v0. Traveling on a circular path, the ball comes to a halt at point B. What enables the ball to reach point B, which is above point A? Ignore friction and air resistance.

From conservation of energy which states that energy can neither be created nor be destroyed, but can be transformed from one form to another.

Ki+Ui=Kf+Uf

Ki=initial kinetic energy

Ui=initial potential energy

Kf=final kinetic energy

Uf=final potential energy

we know that \frac{1}{2} mu^{2} +mgha=\frac{1}{2} mv^{2} +mghb

m=mass of the ball

ha=downward height a

hb=upward height b

u=initial velocity u

v=final velocity v, which is 0

g=acceleration due to gravity

v=0 at final velocity

1/2mu^2+mgha=0+1/2mv^2

ha=hb+Ki/mh

From the above equation, we can conclude that the ball's initial kinetic energy  is responsible for making the ball reach point B.

Point B is higher than point A from the motion gained by the ball

3 0
3 years ago
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