Answer:
6.88 mA
Explanation:
Given:
Resistance, R = 594 Ω
Capacitance = 1.3 μF
emf, V = 6.53 V
Time, t = 1 time constant
Now,
The initial current, I₀ = 
or
I₀ = 
or
I₀ = 0.0109 A
also,
I = ![I_0[1-e^{-\frac{t}{\tau}}]](https://tex.z-dn.net/?f=I_0%5B1-e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%7D%5D)
here,
τ = time constant
e = 2.717
on substituting the respective values, we get
I = ![0.0109[1-e^{-\frac{\tau}{\tau}}]](https://tex.z-dn.net/?f=0.0109%5B1-e%5E%7B-%5Cfrac%7B%5Ctau%7D%7B%5Ctau%7D%7D%5D)
or
I = ![0.0109[1-2.717^{-1}]](https://tex.z-dn.net/?f=0.0109%5B1-2.717%5E%7B-1%7D%5D)
or
I = 0.00688 A
or
I = 6.88 mA
3 is the answer to your question
Answer:
Mc = 1920[lb*in]
Explanation:
Para poder solucionar este problema debemos realizar un análisis estático, por tal motivo lo primero es realizar un diagrama de cuerpo libre con las respectivas fuerzas actuando sobre la barra ABC. DE igual manera calcular la geometría de la configuración mostrada.
El diagrama de cuerpo libre se puede ver en la imagen adjunta, con la solución de este problema.
Lo primero es determinar el angulo t, el cual por medio de las propiedades del triangulo rectángulo se puede determinar.
Con este angulo (t) ya determinado, fijamos la atención en el triangulo BCD, este triangulo no es rectángulo, pero por medio de la ley de senos podemos determinar el angulo omega.
Después de determinar el angulo omega, restamos el angulo (t) para poder determinar el angulo (a).
Seguidamente realizamos una sumatoria de momentos alrededor del punto C, utilizado las respectivas fuerzas con los ángulos descompuestos.
El momento en el punto C es de 1920 [Lb*in].
Nota: ya que no se menciona la fuerza en el punto A, esta se desprecia y no se tiene en cuenta en los calculos. En la imagen adjunta se puede ver el procedimiento desarrollado.
Electricity is NOT a part of electromagnetic spectrum.
An electromagnetic spectrum contains electromagnetic radiations arranged according to frequencies and wavelength.
<h2>Further Explanation
</h2><h3>Electromagnetic waves </h3>
- Electromagnetic waves are types of waves that do not require a material medium for transmission.
- These waves are mostly transverse in nature, which means the direction of transmission is perpendicular to the direction of vibration of particles.
- They include, light waves, radio waves, x-rays, infra-red, etc.
<h3>Electromagnetic spectrum
</h3>
- An electromagnetic wave shows electromagnetic waves arranged according to frequencies and wavelength.
- Electromagnetic spectrum contains electromagnetic waves: Gamma rays, x-rays, Ultraviolet, Visible light, infra-red, microwaves, and radio waves.
- The electromagnetic spectrum is divided into various sections based on wavelength, with gamma rays having the shortest wavelength and radio waves having the longest wavelength.
- The part of the electromagnetic spectrum that we can see using our naked eyes is called the visible light spectrum.
- In order of frequency, the radio waves have the lowest frequency while gamma rays have the largest frequency.
<h3>General characteristics of electromagnetic waves </h3>
- They travel with the speed of light (3.0 x 10^8 m/s)
- They possess energy that is given by; E =hf, where h is the plank’s constant and f is the frequency.
- They are transverse in nature, and therefore, the wavelength is measured between successful crests or troughs.
- They can travel through vacuum
Keywords: Electromagnetic spectrum, electromagnetic waves.
<h3>Learn more about: </h3>
Level: High school
Subject: Physics
Topic: Electromagnetic spectrum
Answer:
Explanation:
The Planck Eistein relation, states that the energy of a photon is proportional to its frequency:
h is the Plank constant.The frequency of a photon is defined as the speed of light over its wavelength:
Replacing (2) in (1):
