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-Dominant- [34]
3 years ago
13

I am pushing on a box with 15 N of force, and my younger cousin is pushing the box (in the same direction as me) with 10 N of fo

rce. How much is the net force on the box?
Help
Physics
1 answer:
Greeley [361]3 years ago
6 0
25N
:)
Hope this helps
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Answer:

1.736m/s²

Explanation:

According to Newton's second law;

\sum F_x = ma_x\\

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Ff is the frictional force acting on the body

Ff = \mu R\\Ff = \mu mg\\

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Substitute the given parameters

Fm - \mu mg = ma\\70 - 0.18(20)(9.8) = 20a\\70-35.28 = 20a\\34.72 = 20a\\a = \frac{34.72}{20}\\a =  1.736m/s^2\\

Hence the deceleration rate of the wagon as it is caught is 1.736m/s²

7 0
3 years ago
A. Describe one meal that you typically order when eating out.
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3 years ago
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