A :-) a = v^2 by r
Given - radius = 25 m
velocity = 10 m/s
Solution -
a = v^2 by r
a = ( 10 )^2 by 25
a = 100 by 25
( cut 25 and 100 because 25 x 4 = 100 )
a = 4 m/s^2
.:. The centripetal acceleration of the car
= 4 m/s^2.
The answer is A. waterfall
To be considered as an engine , it should be a Man-made objects that could be used to produce power that creates motions.
From all the options above could be used to produce such power, but the waterfall is not made by mandkind
Answer:
Any object moving in a circle (or along a circular path) experiences a centripetal force. That is, there is some physical force pushing or pulling the object towards the center of the circle. This is the centripetal force requirement.
Explanation:
Mass of Tracey M1 = 32 kg
Mass of Jonas M2 = 45 kg
Initially both were at rest
so V1i = V2i =0
after pushing each other Jonas speed V2f = 0.80 m/s
we need to find out final speed of Tracy
Here we can use momentum conservation as no external force is acting here
M1V1i + M2V2i = M1V1f + M2V2f
32(0) + 45(0) = 32 V1f + 45(0.80)
0 = 32 V1f + 36
-36 = 32 V1f
V1f = - 1.125 m/s
negative sign shows that Tracy will move opposite to the Jonas
so answer in two significant figure would be
V1f = 1.1 m/s
Answer:
1178 nm
Explanation:
We are given that
Wavelength of light=

We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.
Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.
The light passes through air film is two times then the change in air film thickness from one edge to other is two times the wavelength of light.
Change in air film thickness from one edge to other edge is same as the thickness of spacer.
Therefore, thickness of spacer=
Thickness of spacer=
m
Thickness of spacer=1178 nm
Hence, the thickness of spacer=1178 nm