A 15kg object strikes the ground with 2000J of kinetic energy after freely falling from rest. How far above the ground was the o
1 answer:
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Data:
n (Wave node)
V (Wave belly)
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
Wire 2 → 2º Harmonic → n = 2
Wire 1 → 1º Harmonic or Fundamental rope → n = 1
If, We have:
V = 42L
Soon:
Answer:
<span>The fundamental frequency of the string:
</span>21 Hz
n (Wave node)
V (Wave belly)
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
Wire 2 → 2º Harmonic → n = 2
Wire 1 → 1º Harmonic or Fundamental rope → n = 1
If, We have:
V = 42L
Soon:
Answer:
<span>The fundamental frequency of the string:
</span>21 Hz
Answer:
θ = (7π / 3) rad
Explanation:
given,
displacement of simple harmonic motion along x-axis
equation is given as
x = 5 sin (π t + π/3 )
general equation of simple harmonic motion
x = A sin θ
θ is the phase angle
θ = π t + π/3
at t = 2 s
Phase of the motion at t =2 s is θ = (7π / 3) rad