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Ne4ueva [31]
3 years ago
13

A Continental rift is also called a

Chemistry
1 answer:
eimsori [14]3 years ago
8 0
It's also called a continental<span> plate, convergent or divergent boundary, or c</span>ontinental<span> drift.</span>
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What is the main reason scientists perform experiments
Anuta_ua [19.1K]
B, they then interpret that data to find their answers
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3 years ago
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I need someone to answer these.
SCORPION-xisa [38]

Answer:

The identity of an atom is determined my the number of <u>protons</u>. This is the <u>atomic number</u>.

The particle(s) found inside the nucleus are called <u>protons and neutrons</u>. Their combined mass is referred to as <u>the mass number</u>.

Isotopes have the same number of <u>protons</u>, but different number of <u>neutrons</u>.

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Calculate the [H+] and pH of a 0.0040 M hydrazoic acid solution. Keep in mind that the Ka of hydrazoic acid is 2.20×10−5. Use th
Vera_Pavlovna [14]

Answer:

[H^+]=0.000285

pH=3.55

Explanation:

In this, we can with the <u>ionization equation</u> for the hydrazoic acid (HN_3). So:

HN_3~~H^+~+~N_3^-

Now, due to the Ka constant value, we have to use the whole equilibrium because this <u>is not a strong acid</u>. So, we have to write the <u>Ka expression</u>:

Ka=\frac{[H^+][N_3^-]}{[HN_3]}

For each mol of H^+ produced we will have 1 mol of N_3^-. So, we can use <u>"X" for the unknown</u> values and replace in the Ka equation:

Ka=\frac{X*X}{[HN_3]}

Additionally, we have to keep in mind that HN_3 is a reagent, this means that we will be <u>consumed</u>. We dont know how much acid would be consumed but we can express a<u> subtraction from the initial value</u>, so:

Ka=\frac{X*X}{0.004-X}

Finally, we can put the ka value and <u>solve for "X"</u>:

2.2X10^-^5=\frac{X*X}{0.004-X}

2.2X10^-^5=\frac{X^2}{0.004-X}

X= 0.000285

So, we have a concentration of 0.000285 for H^+. With this in mind, we can calculate the <u>pH value</u>:

pH=-Log[H^+]=-Log[0.000285]=3.55

I hope it helps!

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3 years ago
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no, u will have to soak then in order for them to die  

4 0
3 years ago
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Chemistry! Help! Please!
Ratling [72]

Question 1

The correct answer is a.

Explanation

The relationship between pH and pOH is given by

pH + pOH = 14, We can use pH=-log[H^+] and pOH= -log[OH^-]. In a we are given the concentration of [OH] and so we use that to find the pOH, then from pOH we can find the pH.

pOH= -log [2.4 \times 10^-^2] = 1.62\\\\pH = 14 - 1.62= 12.38

b.pH=-log(1.53 \times 10^-^2) = 1.82

c. HCl is a strong acid so it dissociates to 0.0001 H^+ and 0.0001 Cl^-, hence

pH= -log[0.0001] = 4

d.pOH= -log [4.4 \times 10^-9] = 8.36\\\\pH= 14- 8.36 = 5.64

a.[OH^-] = 2.4 \times 10^-^2 has a pH 12.36 which is greater than 7

Question 2

The correct answer is d O_2(g).

Explanation

This is because solids and liquids do not appear in the equilibrium constant expression. Since K= \frac{[products]}{[reactants]}.

For the equation

2PbS_(_s_) + 3O_2_(_g_) + C_(_s_) \implies 2Pb _(_s_) + CO_2_(_g_) + SO_2(_g_)

K= \frac{[CO_2][SO_2]}{[O_2]}

Question 3

The correct answer is c

In a molecule the oxidation number are assigned to get the sum of a neutral charge or ion. The overall charge of SO_4^2^- is -2 and in all its compounds oxygen has -2 charge, hence

S+ 4O = -2\\S+4(-2)=-2\\\implies S= -2 +8 = +6

Question 4

The correct answer is b. An oxidising agent must gain electrons in a reaction, thus it is the one that undergoes reduction.In order find out what is being reduced we write half reactions for molecules that change their state. Ag^+ and K^+ are spectactor ions in this reaction.

Cl_2 + 2e \implies 2Cl^-\\\\NO_2 +H_2O \implies NO_3 +2H^+ +2e\\\\H^+ + OH^- \implies H_2O\\

In the chloride half reaction Cl_2 gains electrons to become Cl^- ions.

Question 5

The last element D is correct. When a nucleus decays by beta emission it produces a daughter nucleus that has same mass number but different atomic number. Therefore beta-decay will have equation

\frac{187}{75} Re \implies \frac{187}{76} Os + \beta

Question 6

The correct answer is a. A beta particle is an electron because it has a charge of -1 and has same mass as an electron, while a positron is  a particle with the same mass as an electron  but with a positive charge.

4 0
3 years ago
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