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nadya68 [22]
3 years ago
10

Question 2 The metal molybdenum becomes superconducting at temperatures below 0.90K. Calculate the temperature at which molybden

um becomes superconducting in degrees Celsius. Round your answer to 2 decimal places.
Chemistry
1 answer:
LenKa [72]3 years ago
5 0

Answer:

Temperature at which molybdenum becomes superconducting is-272.25°C

Explanation:

Conductor are those hard substances which allows path of electric current through them. And super conductors are those hard substances which have resistance against the flow of electric current through them.

As given, molybdenum becomes superconducting at temperatures below 0.90 K.

Temperature in Kelvins can be converted in °C by relation:

T(°C)=273.15-T(K)

Molybdenum becomes superconducting in degrees Celsius.

T(°C)=273.15-0.90= -272.25 °C

Temperature at which molybdenum becomes superconducting is -272.25 °C

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Answer:

B) Add appropriate quantities of weak acid and its conjugate base to water.

C) Partially neutralize a weak acid solution by addition of a strong base.

(D) Partially neutralize a weak base solution by addition of a strong acid.

Explanation:

A buffer solution is made by a weak acid and its conjugated base or a weak base and its conjugated acid.

If you add a weak acid to water, you can adjust the pH of the buffer solution by adding a strong base.

If ypu add a weak base to water, you can adjust the pH of the buffer solution by adding a strong acid.

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For the following reaction,
jeka94

Answer:

The answer to your question is:

1.- CO

2.- 0.414 moles of CO2

Explanation:

Data

                               2CO   + O2      ⇒    2CO2

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O2 = 0.418

 

Process

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Then the limiting reactant is CO

2.-

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                   x = 0.414 moles of CO2

                   

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