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3 years ago

What is the volume of a bar of soap that is 9 cm long, 5 cm wide, and 2 cm high?

Physics

2 answers:

GalinKa [24]3 years ago

7 0

Answer:

90cm

Explanation:

2x5=10

10x9=90

Nataly_w [17]3 years ago

3 0

Answer:

90 cm

Explanation:

To find volume, the formula is V=LWH

L is the length, W is the width and H is the height:

9 x 5 x 2 = 90

So V = 90 cm

Hope this helps you out! : )

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Blababa [14]

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a) 404 m² b) apparent height = 7.5 m

Explanation:

This question is about refraction and total internal refraction.

Here I will take refractive index of air and water

$n_{air}=1\\ n_{water}=1.33=4/3$

Now let's look at the diagram I have attached here

At some angle A, the light from the ring (yellow point) under water will be totally internally refracted (B = 90°), which means that rays of light (yellow arrow) that make large enough angle A will not be able to escape from the water. Since we assumed that the ring is a point, there will be a critical cone of angle A with the ring at its apex which traces a circle of radius R on the surface of water, which, beyond this radius, no light could escape.

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$\frac{sin(B)}{sin(A)} = \frac{n_{water}}{n_{air}} = 4/3$

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$\frac{3)}{4}sin(B) = [tex]\frac{3}{4} sin(90^\circ ) = 0.75 = sin(A)$

Therefore

$A = 48.6^\circ$

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$h* tan (A) = R\\R =11.3 m$

And with that we can find the area

$A = \pi R^2=404\ m^2$

Additional Problem

For apparent depth from above, we can think that, since we are accustomed to seeing light at the speed of c in air, our brain interpret light from any source to be traveling at c. This causes light that originated under water, which has the speed of

$v_{water} = \frac{c}{n_{water}} = 0.75c$

to appear as if it has traveled with the same duration as light with speed c

In order for this to happen our brain perceive shortened length which is the apparent depth.

To put it in mathematical term

$t_{travel}=\frac{h_{apparent}}{v_{water}} =\frac{h}{c}$

So we get apparent depth

$h_{apparent}=0.75h = 7.5\ m$

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