1) -3(5x+2y=-3)⇒ -15x-6y=9
⇒ -9x=27
2(3x+3y=9)⇒ 6x+6y=18
2) -9x/-9=27/-9 ⇒ x=-3
3) 3(-3)+3y=9⇒ -9+9+3y=9+9⇒ 3y/3=18/3⇒ y=6
Answer: (-3,6)
Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
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Step 2) Once y is eliminated, solve for x.
Step 3) Now plug x back into one of the original equations and solve for y. <em>Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,</em>
2 ways
zero product property
easy way
zero product
factor perfect square
m^2-3^2=0
(m-3)(m+3)=0
set each to zero
m-3=0
x=3
m+3=0
m=-3
m=-3 or 3
easy way
add 9 to both sides
m^2=9
sqrt both sides remember to take postive and negative roots
m=+/-3
m=-3 or 3
B is answer
The answer is 150 because 30+150=180
Answer:
32760
Step-by-step explanation:
This is a permutation of 15 objects taken 4 at a time. To calculate this, we use the formula:

In our case, n is 15 and r is 4:

Answer:
The actual distance between the historical markers is 18 miles.
Step-by-step explanation:
Given : On a map, the distance between two historical markers is 4.5 inches, and 2.5 inches represents 10 miles.
To find : What is the actual distance between the historical markers?
Solution :
We have given that,
2.5 inches represents 10 miles.
i.e, 1 inch represent
miles.
1 inch = 4 miles.
Now, The distance between two historical markers is 4.5 inches.
The actual distance between the historical markers in 4.5 inch is


Therefore, The actual distance between the historical markers is 18 miles.