Derek is playiag hide-and-seek with Sasha and Frank. Sasha is hiding 12 meters south of

Helen [10]

$\frac{3}{5}$ × $4 \frac{1}{6}$

First, convert $4\frac{1}{6}$ to an improper fraction. Use this rule: $a \frac{b}{c}$ = $\frac{ac+b}{c}$ / Your problem should look like: $\frac{3}{5}$ × $\frac{4x6+1}{6}$
Second, simplify 4 × 6 to 24. / Your problem should look like: $\frac{3}{5}$ × $\frac{24+1}{6}$
Third, simplify 24 + 1 to 25. / Your problem should look like: $\frac{3}{5}$ × $\frac{25}{6}$
Fourth, apply this rule: $\frac{a}{b}$ × $\frac{c}{d}$ = $\frac{ac}{bd}$ / Your problem should look like: $\frac{3x25}{5x6}$
Fifth, simplify 3 × 25 to 75. / Your problem should look like: $\frac{75}{5x6}$
Sixth, simplify 5 × 6 to 30. / Your problem should look like: $\frac{75}{30}$
Seventh, simplify. / Your problem should look like: $\frac{5}{2}$
Eighth, convert to mixed fraction. / Your problem should look like: $2\frac{1}{2}$

Answer: $2 \frac{1}{2}$

5 0

3 years ago

What percentage of videos on the streaming site are between 39 and 189 seconds?

PolarNik [594]

Answer:

B) 15.85%

Step-by-step explanation:

normalcdf(minimum,maximum,μ,σ)

normalcdf(39,189,264,75)

≈0.1573

≈15.73%

Therefore, the closest answer is B

4 0

2 years ago

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

2 years ago

Based on the family the graph below belongs to, which equation could represent the graph?

Ostrovityanka [42]

Answer:

Equation 1 is the equation which represents the graph.

Step-by-step explanation:

6 0

2 years ago

Please help! I’ll give brainliest!:)

bearhunter [10]

Answer:

1467

Step-by-step explanation:

i know this because taking a negative number and a positive is like adding and then you subtract 144 and you get 1467

8 0

2 years ago