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3 years ago

What are the properties of elements??

Chemistry

2 answers:

umka21 [38]3 years ago

8 0

Answer:

Atomic number. The atomic number indicates the number of protons within the core of an atom. ...

. Atomic mass. The name indicates the mass of an atom, expressed in atomic mass units (amu). ...

. Electronegativity according to Pauling. ...

. Density. ...

. Melting point. ...

. Boiling point. ...

. Vanderwaals radius. ...

. Ionic radius.

8090 [49]3 years ago

7 0

Answer:

Chemical properties

Atomic number. The atomic number indicates the number of protons within the core of an atom.

Atomic mass. The name indicates the mass of an atom, expressed in atomic mass units (AMU).

Electronegativity according to Pauling.

Density.

Melting point.

Boiling point.

Vanderwaal's radius.

Ionic radius.

And many more.

Explanation:

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Answer:

$T_f$ = 25.05°C

Explanation:

Given:

the value of ΔHcomb (heat of combustion) for dimethylphthalate (C10H10O4) is = 4685 kJ/mol.

mass = 0.905g of dimethylphthalate

molar mass = 194.18g dimethylphthalate

number of moles of dimethylphthalate = ???

$T_i$ = 21.5°C

$C_{calorimeter}$ = 6.15 kJ/°C

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since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

0.905g of dimethylphthalate × $\frac{1 mole (dimethylphthalate)}{194.184g(dimethylphthalate)}$

number of moles of dimethylphthalate = 0.000466 moles

Heat released = moles of dimethylphthalate × heat of combustion

= 0.000466 moles × 4685 kJ

= 21.84 kJ

∴ Heat absorbed by the calorimeter = $C_{calorimeter}$ $(T_f-T_i} )$

21.84 kJ =6.15 kJ/°C $* (T_f-21,5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f)$ - 132.225 kJ

21.84 KJ + 132.225 kJ = $(6.15 kJ/^0C * T_f)$

154.065 kJ = $(6.15 kJ/^0C * T_f)$

$T_f$ = $\frac{154.065kJ}{6.15kJ/^0C}$

$T_f$ =25.05°C

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What are the properties of elements??​

What are the properties of elements??